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Start by determining how many decimal places there are. Remember that the product of any number of decimals has as many decimal places as all the decimals being multiplied put together, so if .002 is multiplied by itself four times, the product will contain 12 decimal places. Next, get the result. 2^4 = 16, and since that 2 comes at the end of a decimal containing nothing other than zeros, it will come at the very end of the result, and EVERY other digit will be a 0. So there will be twelve digits, two of which are 1 and 6 and the rest of which are 0’s -- the decimal is .000000000016 – so the answer is 10 zeros.
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Re: If .0024 is represented in its shortest possible decimal form, how man [#permalink]

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22 Feb 2015, 19:52

1

This post received KUDOS

Bunuel wrote:

If .002^4 is represented in its shortest possible decimal form, how many 0’s to the right of the decimal point does it contain?

A. 0 B. 8 C. 9 D. 10 E. 11

Kudos for a correct solution.

.002^4= 2/1000^4 or 16/10^12. When you divide 16 by 10^12, two zeros will go in moving decimal point to the left of 1, and there will be 10 zeros left (of the total 12 that 10^12 has). Answer D.
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Re: If .0024 is represented in its shortest possible decimal form, how man [#permalink]

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28 Feb 2015, 10:42

Bunuel wrote:

If .002^4 is represented in its shortest possible decimal form, how many 0’s to the right of the decimal point does it contain?

A. 0 B. 8 C. 9 D. 10 E. 11

Kudos for a correct solution.

We know that 2^4 = 16 Hence the last 2 digits would be 16. Also, there are 3 digits in .002. Hence (3 digits )^4 = 12 digit number Out of these 12 digits, last 2 digits are 16 Hence there are 10 zeros after decimal.

Hence option D.

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If anyone is confused by some of the posts in this thread, it's because they are in response to the original prompt (which had a 'typo' in it). The current prompt is correct as written (we're meant to deal with [.002]^4, not .0024).

Re: If .0024 is represented in its shortest possible decimal form, how man [#permalink]

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19 Oct 2017, 08:44

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