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30 Aug 2018, 05:13
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B
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Difficulty:
25%
(medium)
Question Stats:
73% (01:20) correct
28%
(01:09)
wrong
based on 160
sessions
History
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If 72% of rectangular floor is covered by a rectangular rug that is 9 feet by 16 feet, what is the area, in square feet, of the uncovered floor?
A. 28
B. 56
C. 80
D. 200
E. 560
A. 28
B. 56
C. 80
D. 200
E. 560
30 Aug 2018, 05:45
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Bunuel
If 72% of rectangular floor is covered by a rectangular rug that is 9 feet by 16 feet, what is the area, in square feet, of the uncovered floor?
A. 28
B. 56
C. 80
D. 200
E. 560
A. 28
B. 56
C. 80
D. 200
E. 560
Hi ..
72% of total =9*16
Don't multiply, may save time while dividing..
So \(\frac{72}{100}*total=9*16.......total =9*16*\frac{100}{72}\)
Divide both by 9 first..
\(total = 16*\frac{100}{8}\)
Now divide by 8
\(total=2*100=200\)
Therefore uncovered area = 200-9*16=56
B
Bunuel
If 72% of rectangular floor is covered by a rectangular rug that is 9 feet by 16 feet, what is the area, in square feet, of the uncovered floor?
A. 28
B. 56
C. 80
D. 200
E. 560
A. 28
B. 56
C. 80
D. 200
E. 560
Let the total area be x
we are given 0.72(x)=16*9
=>x=200
Area of uncovered floor is 28% of x = 56
Option B is the Answer.
