Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Dec 1511:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease.
Dec 1608:00 AM PST
-11:59 PM PST
GMAT Club 12 Days of Christmas is a 4th Annual GMAT Club Winter Competition based on solving questions. This is the Winter GMAT competition on GMAT Club with an amazing opportunity to win over $40,000 worth of prizes!- Dec 17
09:00 AM PST
-10:00 AM PST
Join Manhattan Prep instructor Whitney Garner for a fun—and thorough—review of logic-based (non-math) problems, with a particular emphasis on Data Sufficiency and Two-Parts. - Dec 18
10:00 AM PST
-11:00 AM PST
Here is the essential guide to securing scholarships as an MBA student! In this video, we explore the various types of scholarships available, including need-based and merit-based options. - Dec 21
11:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment
25 Nov 2014, 08:24
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
79% (01:26) correct
21%
(01:54)
wrong
based on 110
sessions
History
Date
Time
Result
Not Attempted Yet
If a, b, and c are distinct nonzero numbers, is \(\frac{(a - b)^3(b - c)}{(a + b)^2(b + c)^2} < 0\) ?
(1) a > b
(2) b > c
Source: Chili Hot GMAT
(1) a > b
(2) b > c
Source: Chili Hot GMAT
25 Nov 2014, 10:04
Kudos
Bookmarks
Bunuel
Tough and Tricky questions: Inequalities.
If a, b, and c are distinct nonzero numbers, is \(\frac{(a - b)^3(b - c)}{(a + b)^2(b + c)^2} < 0\) ?
(1) a > b
(2) b > c
Kudos for a correct solution.
Source: Chili Hot GMAT
\(\frac{(a - b)^3(b - c)}{(a + b)^2(b + c)^2} < 0\)
(a + b)^2 and (b + c)^2 will always be positive
(1) a > b
a-b>0 thus (a - b)^3 is positive but we have no information about (b-c) thus not sufficient
(2) b > c
b-c>0 but no info about a and b. Not sufficient
combining 1 and 2
a-b>0 and b-c>0 then
\(\frac{(a - b)^3(b - c)}{(a + b)^2(b + c)^2}\) will always be greater then 0.
Sufficient. [C]
25 Nov 2014, 10:15
Kudos
Bookmarks
I will go with (C) again not sure though
Denominator will always be +ve since the numbers are distinct and non zero (i think this assumption is incorrect because if a=2, b=-2 & c=-3 then the denominator is 0 and the fraction is undefined, but anyways)
1. (a-b)^3 will be +ve if a>b and then (b-c) has to be -ve meaning b<c
2. (b-c) will be +ve if b>c and then (a-b)^3 has to be -ve meaning a<b
Combining the two 1 & 2 we will always get greater than 0
Not convinced with the question because of the assumption above.
Denominator will always be +ve since the numbers are distinct and non zero (i think this assumption is incorrect because if a=2, b=-2 & c=-3 then the denominator is 0 and the fraction is undefined, but anyways)
1. (a-b)^3 will be +ve if a>b and then (b-c) has to be -ve meaning b<c
2. (b-c) will be +ve if b>c and then (a-b)^3 has to be -ve meaning a<b
Combining the two 1 & 2 we will always get greater than 0
Not convinced with the question because of the assumption above.
