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If a, b, c and d are consecutive integers (a < b < c < d). What is the

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Bunuel
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If a, b, c and d are consecutive integers (a < b < c < d). What is the [#permalink] New post   Updated on: 14 Oct 2019, 18:53
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If a, b, c and d are consecutive integers (a < b < c < d). What is the value of (d + c) - (b + a) ?

A. 1.
B. 2.
C. 3.
D. 4.
E. 0.
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D

Originally posted by Bunuel on 12 Sep 2019, 01:28.
Last edited by chetan2u on 14 Oct 2019, 18:53, edited 1 time in total.
Corrected the OA
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Re: If a, b, c and d are consecutive integers (a < b < c < d). What is the [#permalink] New post   12 Sep 2019, 01:46
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Bunuel wrote:
If a, b, c and d are consecutive integers (a < b < c < d). What is the value of (d + c) - (b + a) ?

A. 1.
B. 2.
C. 3.
D. 4.
E. 0.


Let, a, b, c, and d are 1, 2, 3, 4 respectively

d+c = 4+3 = 7

b+a = 2+1 = 3

i.e. (d + c) - (b + a) = 7-3 = 4

Answer: Option D
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Re: If a, b, c and d are consecutive integers (a < b < c < d). What is the [#permalink] New post   17 Sep 2019, 08:17
Let a,b,c,d be n, n+1, n+2, n+3 respectively.

(d+c) - (b+a)
= (n+3+n+2) - (n+1+n)
= 2n + 5 - 2n - 1
= 4

Is the OA wrong? Because the answer I got is 4.


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Re: If a, b, c and d are consecutive integers (a < b < c < d). What is the [#permalink] New post   17 Sep 2019, 08:48
NiyatiM wrote:
Let a,b,c,d be n, n+1, n+2, n+3 respectively.

(d+c) - (b+a)
= (n+3+n+2) - (n+1+n)
= 2n + 5 - 2n - 1
= 4

Is the OA wrong? Because the answer I got is 4.


--Niyati Muchhala--

Posted from my mobile device

You're right dear!.
I got 4 too.
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Re: If a, b, c and d are consecutive integers (a < b < c < d). What is the [#permalink] New post   14 Oct 2019, 18:51
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Bunuel chetan2u Can you please correct the OA here? :)
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Re: If a, b, c and d are consecutive integers (a < b < c < d). What is the [#permalink]
14 Oct 2019, 18:51
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