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If r(r-4)=12 where r represents a positive integer, then

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If r(r-4)=12 where r represents a positive integer, then  [#permalink]

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New post 05 Feb 2020, 07:17
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If \(r(r-4)=12\) where r represents a positive integer, then \((r-2)^2 +10= \)

A 18
B 26
C 36
D 40
E 52

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Re: If r(r-4)=12 where r represents a positive integer, then  [#permalink]

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New post 05 Feb 2020, 07:26
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If \(r(r−4)=12\) where r represents a positive integer, then \((r−2)^2+10\)=?

A 18
B 26
C 36
D 40
E 52

\(r(r−4)=12\) -> \(r^2−4r-12=0\) -> \((r-6)(r+2) = 0\) -> r=6, r=-2 -> Since r is positive only r=6 is valid

\((r−2)^2+10\)= \(r^2-4r+14\) = \(36-24+14 = 26\) -> Answer - B
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Re: If r(r-4)=12 where r represents a positive integer, then  [#permalink]

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New post 05 Feb 2020, 07:53
1
B.26
r(r-4)=12
r²-4r=12
r²-4r-12=0
we will maje factorize
r_____-6
r_____2
so,r=6




(r-2)²=-10
r²-4r+4=-10
r²-4r=-14
r=6,so, 36-24=-14
12+14=26

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Re: If r(r-4)=12 where r represents a positive integer, then  [#permalink]

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New post 09 Feb 2020, 04:20
SajjadAhmad wrote:
If \(r(r-4)=12\) where r represents a positive integer, then \((r-2)^2 +10= \)

A 18
B 26
C 36
D 40
E 52


Simplifying the given equation, we have:

r^2 - 4r = 12

Foiling the final expression, we have:

r^2 - 4r + 4 + 10 = ?

Since r^2 - 4r = 12, we have:

12 + 4 + 10 = 26

Answer: B

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Re: If r(r-4)=12 where r represents a positive integer, then   [#permalink] 09 Feb 2020, 04:20
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