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31 Dec 2018, 15:10
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
28% (01:59) correct
72%
(01:28)
wrong
based on 102
sessions
History
Date
Time
Result
Not Attempted Yet
If the range of the six positive numbers 4,3,14,7,10 and x is 14, what is the difference between the greatest possible value of x and least possible value of x?
(A) 0
(B) 11
(C) 14
(D) 17
(E) 20
(A) 0
(B) 11
(C) 14
(D) 17
(E) 20
31 Dec 2018, 21:09
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Mahmoudfawzy83
For all those who have answered wrong, the importance of reading the question for minor details is very important, as POSITIVE word here
The numbers can be written in an ascending order as 3,4,7,10, and 14, and X can fit in somewhere in the series..
Now the range is 14, means difference between the largest and smallest term is 14
As the range without x is 14-3=11, x will be either the largest or smallest
1) let 14 be the highest then smallest will be 14 - 14=0.
This means x is 0, but it is given that X is positive number so X>0.... Not possible
2) let 3 be the minimum, then largest will be 3+14=17
So X is 17..
Thus, the only possible way the range is 14 is 3, 4, 7, 10, 14, 17
So X can be only 17..
Minimum value of x = Maximum value of x=17
Answer = 17-17=0
A
02 Jan 2019, 04:19
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Solution
Given:
- • Range of six positive i=numbers, {4, 3, 14, 7, 10, x} = 14
To find:
- • The difference between maximum and minimum possible values of x
Approach and Working:
- • If x > 14, then x is the maximum value of the set
• And, range will be x – 3 = 14
- o Implies, x = 17
• If x < 14, then 14 is the maximum value of the set
• And, for x to be minimum, x must be the minimum value of the set. So, range will be 14 – x = 14
- o Implies, x = 0
o But we know x is positive. So, this case is not valid
Thus, x can take only one value = 17
- • Therefore, maximum value – minimum value = 17 – 17 = 0
Hence, the correct answer is Option A
Answer: A
