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If x and y are integers, is x > y?

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If x and y are integers, is x > y?  [#permalink]

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New post 01 Jul 2017, 00:21
00:00
A
B
C
D
E

Difficulty:

  65% (hard)

Question Stats:

40% (01:39) correct 60% (01:37) wrong based on 100 sessions

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GMAT 1: 630 Q47 V29
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Re: If x and y are integers, is x > y?  [#permalink]

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New post 01 Jul 2017, 00:48
Bunuel wrote:
If x and y are integers, is x > y?

(1) 0 < x^y < 1
(2) y is odd



(1) 0 < x^y<1
this can only happen
when y is negative

if x is positive
x can be greater than or less than y depending upon whether y is even or odd
y=even, x<y or x>y
y= odd, x>y
if x is negative
x can be greater than y or less than y depending upon whether y is even or odd
y=even, x<y or x>y
Not sufficient

(2) y is odd
Not sufficient

On combining both we can answer the question
Hence C
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Re: If x and y are integers, is x > y?  [#permalink]

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New post 01 Jul 2017, 15:21
Bunuel wrote:
If x and y are integers, is x > y?

(1) 0 < x^y < 1
(2) y is odd


(1) If x^y is positive, then x is positive. If it is less than one, then y is negative. Sufficient.
(2) y could be positive or negative, insufficient.

Answer A.
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Re: If x and y are integers, is x > y?  [#permalink]

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New post 02 Jul 2017, 20:21
Bunuel wrote:
If x and y are integers, is x > y?

(1) 0 < x^y < 1
(2) y is odd



1) if x^y is less than 1, it does'nt matter if y is odd or even. To satisfy this condition, x has to be positive and y has to be negative. Hence x > y. Suff
2) No information about x. x can be anything here. Not Suff.
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Re: If x and y are integers, is x > y?  [#permalink]

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New post 02 Jul 2017, 23:29
1
This one can be tricky if you rush through it.

As some users have posted, at first glance, it appears that x must be positive however it is important to remember that even exponents can mask signs or make negative numbers into positive.

Consider x = -2;
Is there any power we can raise -2 to to make it a positive fraction less than 1?
Well to make it positive we have to raise it to an even exponent and to make it a fraction we have to raise it to a negative exponent; Thus raising it to a negative even exponent could satisfy the requirements.
Both y = -2 and y = -4 work, however they give different answer to the question "is x>y?" thus more information is needed.

To finish this off quickly - the 2nd statement tells us very little on its own so we'll need to combine it with statement I;
y is odd means that x cannot be negative as there is no way we can make it a positive number;
Together this information is sufficient
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Re: If x and y are integers, is x > y?   [#permalink] 02 Jul 2017, 23:29
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