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Re: If X is a positive integer, what is the remainder when X^2 is divided [#permalink]
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Kudos
Statement 1 and 2 are clearly insufficient alone

Combining both equations
X is a prime number greater than or equal to 5

X=6k±1

\(X^2=36k^2±12k+1\)
Hence \(X^2=1 (mod 6)\)

firas92 wrote:
If \(X\) is positive integer, what is the remainder when \(X^2\) is divided by 6?

1. \(X≥5\)

2. \(X\) has no factor P such that \(1<P<X\)
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Re: If X is a positive integer, what is the remainder when X^2 is divided [#permalink]
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Re: If X is a positive integer, what is the remainder when X^2 is divided [#permalink]
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