If x is the least of three consecutive even integers, what is the product of these three integers in terms of x?

A. \(x^3 + 6x^2 + 8x\)

B. \(x^3 – 3x^2 + 2x\)

C. \(x^3 – 3x^2 - 2x\)

D. \(x^3 – x^2\)

E. \(x^3 – x\)
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

The three consecutive even integers would be \(= x , (x + 2), (x + 4)\)

Product of these 3 integers would be;

\(x(x+2)(x+4)\)

\(x(x^2+ 2x + 4x + 8)\)

\(x(x^2 + 6x + 8)\)

\(x^3 + 6x^2 + 8x\) . Answer (A) ...

Let x be the least even integer of the consecutive integers.
So, the other even integers will be (x+2) and ( x+4)

The product of the integers = x(x+2)(x+4) = (x^2+2x) (x+4) = (x^3 + 6x^2 + 8x)



Answer A
_________________

CAT 99th percentiler : VA 97.27 | DI-LR 96.84 | QA 98.04 | OA 98.95
UPSC Aspirants : Get my app UPSC Important News Reader from Play store.

MBA Social Network : WebMaggu


Appreciate by Clicking +1 Kudos ( Lets be more generous friends.)

What I believe is : "Nothing is Impossible, Even Impossible says I'm Possible" : "Stay Hungry, Stay Foolish".

three consecutive even integers: x, x+2, x+4

product: x (x^2 + 6x + 8)

IMO A

Based on given information we have \(x, x+2, x+4\) and we need to find the product of these numbers.

\((x)(x+2)(x+4)\)

\((x)(x^2+4x+2x+8)\)

\((x)(x^2+6x+8)\)

\(x^3 + 6x^2 + 8x\)

Hence, Answer is A
_________________

"Nothing in this world can take the place of persistence. Talent will not: nothing is more common than unsuccessful men with talent. Genius will not; unrewarded genius is almost a proverb. Education will not: the world is full of educated derelicts. Persistence and determination alone are omnipotent."

Best AWA Template: https://gmatclub.com/forum/how-to-get-6-0-awa-my-guide-64327.html#p470475

Speed tip
you don't have to multiply x(x+2)(x+3), all options have a negative sign except A

note the abundance of minus signs in B-E
if 2*4*6=48,
only A>8