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If x is the least of three consecutive even integers, what is the prod
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22 Jun 2017, 04:40
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Re: If x is the least of three consecutive even integers, what is the prod
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22 Jun 2017, 04:51
Answer is A. Assuming numbers consecutive even integers 2, 4 and 6, we get x = 2
so, the product should be 2*4*6=48
Substituting x=2 in answer choices, only A gives us 48, hence the answer



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Re: If x is the least of three consecutive even integers, what is the prod
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22 Jun 2017, 04:53
Bunuel wrote: If x is the least of three consecutive even integers, what is the product of these three integers in terms of x?
A. \(x^3 + 6x^2 + 8x\)
B. \(x^3 – 3x^2 + 2x\)
C. \(x^3 – 3x^2  2x\)
D. \(x^3 – x^2\)
E. \(x^3 – x\) The three consecutive even integers would be \(= x , (x + 2), (x + 4)\)
Product of these 3 integers would be;
\(x(x+2)(x+4)\)
\(x(x^2+ 2x + 4x + 8)\)
\(x(x^2 + 6x + 8)\)
\(x^3 + 6x^2 + 8x\) . Answer (A) ...



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If x is the least of three consecutive even integers, what is the prod
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22 Jun 2017, 04:59
Bunuel wrote: If x is the least of three consecutive even integers, what is the product of these three integers in terms of x?
A. \(x^3 + 6x^2 + 8x\)
B. \(x^3 – 3x^2 + 2x\)
C. \(x^3 – 3x^2  2x\)
D. \(x^3 – x^2\)
E. \(x^3 – x\) Lowest is x hence x, x+2, x+4 On multiplication we will get \(x^3 + 6x^2 + 8x\) Hence A
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Re: If x is the least of three consecutive even integers, what is the prod
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22 Jun 2017, 05:34
Bunuel wrote: If x is the least of three consecutive even integers, what is the product of these three integers in terms of x?
A. \(x^3 + 6x^2 + 8x\)
B. \(x^3 – 3x^2 + 2x\)
C. \(x^3 – 3x^2  2x\)
D. \(x^3 – x^2\)
E. \(x^3 – x\) Let x be the least even integer of the consecutive integers. So, the other even integers will be (x+2) and ( x+4) The product of the integers = x(x+2)(x+4) = (x^2+2x) (x+4) = (x^3 + 6x^2 + 8x) Answer A
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Re: If x is the least of three consecutive even integers, what is the prod
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22 Jun 2017, 06:45
Bunuel wrote: If x is the least of three consecutive even integers, what is the product of these three integers in terms of x?
A. \(x^3 + 6x^2 + 8x\)
B. \(x^3 – 3x^2 + 2x\)
C. \(x^3 – 3x^2  2x\)
D. \(x^3 – x^2\)
E. \(x^3 – x\) Check using the least even integers  2 , 4 & 6 , product is 48 (A) 8 + 6*4 + 8*2 = 48 We don't need to go any further, just plugin in three numbers and checking option (A) confirms the answer.....
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Re: If x is the least of three consecutive even integers, what is the prod
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22 Jun 2017, 11:04
three consecutive even integers: x, x+2, x+4
product: x (x^2 + 6x + 8)
IMO A



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Re: If x is the least of three consecutive even integers, what is the prod
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24 Jun 2017, 07:28
Bunuel wrote: If x is the least of three consecutive even integers, what is the product of these three integers in terms of x?
A. \(x^3 + 6x^2 + 8x\)
B. \(x^3 – 3x^2 + 2x\)
C. \(x^3 – 3x^2  2x\)
D. \(x^3 – x^2\)
E. \(x^3 – x\) The smallest even integer is x, the next consecutive even integer is (x + 2), and the third consecutive even integer is (x + 4). We can express the product of our 3 integers as: x(x + 2)(x + 4) = x(x^2 + 6x + 8) = x^3 + 6x^2 + 8x Answer: A
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Re: If x is the least of three consecutive even integers, what is the prod
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24 Jun 2017, 12:37
Based on given information we have \(x, x+2, x+4\) and we need to find the product of these numbers. \((x)(x+2)(x+4)\) \((x)(x^2+4x+2x+8)\) \((x)(x^2+6x+8)\) \(x^3 + 6x^2 + 8x\) Hence, Answer is A
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Re: If x is the least of three consecutive even integers, what is the prod
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03 Dec 2017, 01:47
Three consecutive EVEN Integers are 2n, 2n+2 & 2n+4 As per the given info the smallest even integer is x . Therefor 2n=x, 2n+2=x+2 & 2n+4=x+4
Product of x, x+2 & x+4 = x*(x+2)*(x+4) = x*(x^2+6x+8) = x^3+6x^2+8x
Ans A
Rgds Dinesh



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Re: If x is the least of three consecutive even integers, what is the prod
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25 Jan 2018, 04:54
Speed tip you don't have to multiply x(x+2)(x+3), all options have a negative sign except A



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If x is the least of three consecutive even integers, what is the prod
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19 Mar 2018, 08:29
Bunuel wrote: If x is the least of three consecutive even integers, what is the product of these three integers in terms of x?
A. \(x^3 + 6x^2 + 8x\)
B. \(x^3 – 3x^2 + 2x\)
C. \(x^3 – 3x^2  2x\)
D. \(x^3 – x^2\)
E. \(x^3 – x\) Say 3 consecutive even integers are\(x, x+2, x+4\) Multiply them, \(x*(x+2)*(x+4)\) \((x^2+2x)*(x+4)\) \(x^3 + 6x^2 + 8x\) (A)
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If x is the least of three consecutive even integers, what is the prod
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19 Mar 2018, 09:43
Bunuel wrote: If x is the least of three consecutive even integers, what is the product of these three integers in terms of x?
A. \(x^3 + 6x^2 + 8x\)
B. \(x^3 – 3x^2 + 2x\)
C. \(x^3 – 3x^2  2x\)
D. \(x^3 – x^2\)
E. \(x^3 – x\) note the abundance of minus signs in BE if 2*4*6=48, only A>8




If x is the least of three consecutive even integers, what is the prod
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19 Mar 2018, 09:43






