aashishagarwal2 wrote:

Geometry PS Question:

In her garden, Mary plants a rose plant and then a jasmine plant 10 yards away from the rose plant. She then plants a lily plant 20 yards away from jasmine. If all the 3 plants are non-collinear, then find the difference between the maximum and the minimum possible distance between the Rose and the lily plant?

I don't have the options to this sum.

I feel solved in my mind and based on logic. I feel the answer should be 11 & 29. Am I correct?

Yes you are right (RJ-JL)<RL<(RJ+JL) which is 10<RL<30. This leaves 29 as maximum value and 11 as minimum value and their difference is 18, which is the answer.