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# In ∆ RST, angle S is a right angle and angle R is 10° greater than ang

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Math Expert
Joined: 02 Sep 2009
Posts: 55236
In ∆ RST, angle S is a right angle and angle R is 10° greater than ang  [#permalink]

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17 Aug 2017, 23:52
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Difficulty:

25% (medium)

Question Stats:

90% (00:35) correct 10% (01:32) wrong based on 31 sessions

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In ∆ RST, angle S is a right angle and angle R is 10° greater than angle T. What is the measure of angle T?

(A) 40°
(B) 45°
(C) 50°
(D) 55°
(E) 80°

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Posts: 140
Location: India
Schools: ISB '20, GMBA '20
Re: In ∆ RST, angle S is a right angle and angle R is 10° greater than ang  [#permalink]

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18 Aug 2017, 00:01
90+T+(T+10)=180
T=40
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Joined: 13 Jul 2015
Posts: 19
Re: In ∆ RST, angle S is a right angle and angle R is 10° greater than ang  [#permalink]

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18 Aug 2017, 01:36
Ans : a - 40 degree

Let angle T be x . Thus angle R= x+10
Some of all the sides of the traingle is 180 degree

GOing by this , x+x+10+90 = 180 degree . Thus x=40 degree

Thus x = 40 degree
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Joined: 14 Sep 2016
Posts: 129
Re: In ∆ RST, angle S is a right angle and angle R is 10° greater than ang  [#permalink]

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18 Aug 2017, 02:02
R = T +10

and S+R+T = 180

We know S = 90

Hence, the above equations we get T = 40

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Re: In ∆ RST, angle S is a right angle and angle R is 10° greater than ang  [#permalink]

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18 Aug 2017, 04:51
Bunuel wrote:
In ∆ RST, angle S is a right angle and angle R is 10° greater than angle T. What is the measure of angle T?

(A) 40°
(B) 45°
(C) 50°
(D) 55°
(E) 80°

1. The remaining angles should be 90 degree.
2. So, R + T should be 90 degree.
3. Since R = 10 + T, so (10+T) + T = 90, thus T = 40 (and R is 50).
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Re: In ∆ RST, angle S is a right angle and angle R is 10° greater than ang   [#permalink] 18 Aug 2017, 04:51
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