gintojin
I am having difficulty understanding the logic path to solving this problem. I see the equations individually and can see the solutions, yet the path for solving this is a challenge for me. Can someone take the time to explain it?
Respectfully, Puzzled.
About the Area of Triangle, There is only one Basic
i.e. Area of Triangle = (1/2) Base of Triangle x Height of triangleYou must Understand that Base can be any side of the triangle but Height in each case will be the perpendicular Distance of Third Vertex pf Triangle from the Base takeni.e. Take area of Triangle LNP and Consider tha Base= LP, Then Height will be the Perpendicular Distance of LP from N i.e. NP=8
i.e. Area of Triangle LNM = (1/2) x LP x 8 = 32 (Given)
i.e. LP = 8Now LNP is a right angle Triangle therefore we can apply Pythagorus Theorem to calculate Hypotenuse of the Triangle
i.e. LN^2 = 8^2 + 8^2
i.e. LN = \(8\sqrt{2}\)
Now Area of LNM = (1/2) LN x 6 = \((1/2) * 8\sqrt{2} * 6 = 24\sqrt{2}\)