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In the diagram to the below, the value of x is closest to which of the
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11 Mar 2020, 08:18
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In the diagram to the below, the value of \(x\) is closest to which of the following? A) \(2+√2\) B) \(2\) C) \(√3\) D) \(√2\) E) \(1\)
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In the diagram to the below, the value of x is closest to which of the
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Updated on: 11 Mar 2020, 17:45
Asad wrote: In the diagram to the below, the value of \(x\) is closest to which of the following?
A) \(2+√2\) B) \(2\) C) \(√3\) D) \(√2\) E) \(1\) Let us drawn AP perpendicular to BC as shown below: Attachment: 111.JPG In triangle APC: Angle ACP = Angle CAP = \(45^o\) => It is a 454590 triangle => AP = PC = AC/\(\sqrt{2}\) = \(x/\sqrt{2}\) => BP = \(x  x/\sqrt{2}\) In right triangle ABP: \(AB^2 = AP^2 + BP^2\) => \(2 = (x/\sqrt{2})^2 + (x  x/\sqrt{2})^2\) => \(2 = x^2/2 + x^2 + x^2/2  2x^2/\sqrt{2}\) => \(2 = x^2 * (2  \sqrt{2})\) => \(x^2 = 2/(2  \sqrt{2}) = ~ 2/0.6 = 3.33\) (approximately) => \(x = \sqrt{3.33} = 1.8\) => Closest value = \(\sqrt{3}\) Answer C
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Originally posted by sujoykrdatta on 11 Mar 2020, 11:39.
Last edited by sujoykrdatta on 11 Mar 2020, 17:45, edited 1 time in total.



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In the diagram to the below, the value of x is closest to which of the
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Updated on: 11 Mar 2020, 18:36
sujoykrdatta wrote: Asad wrote: In the diagram to the below, the value of \(x\) is closest to which of the following?
A) \(2+√2\) B) \(2\) C) \(√3\) D) \(√2\) E) \(1\) Let us drawn AP perpendicular to BC as shown below: Attachment: 111.JPG In triangle APC: Angle ACP = Angle CAP = \(45^o\) => It is a 454590 triangle => AP = PC = AC/\(\sqrt{2}\) = \(x/\sqrt{2}\) => BP = \(x  x/\sqrt{2}\) In right triangle ABP: \(AB^2 = AP^2 + BP^2\) => \(2 = (x/\sqrt{2})^2 + (x  x/\sqrt{2})^2\) => \(2 = x^2/2 + x^2 + x^2/2  2x^2/\sqrt{2}\) => \(2 = x^2 * (2  \sqrt{2})\) => \(x^2 = 2/(2  \sqrt{2}) = ~ 2/0.6 = 3.33\) (approximately) => \(x = \sqrt{3.33} = 1.8\)=> Closest value = 2 Answer B\(√3.33\) = \(1.8\) 1.8 is closed to \(√3\). So the correct choice is C, actually.



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Re: In the diagram to the below, the value of x is closest to which of the
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11 Mar 2020, 12:53
Asad wrote: sujoykrdatta wrote: Asad wrote: In the diagram to the below, the value of \(x\) is closest to which of the following?
A) \(2+√2\) B) \(2\) C) \(√3\) D) \(√2\) E) \(1\) Let us drawn AP perpendicular to BC as shown below: Attachment: 111.JPG In triangle APC: Angle ACP = Angle CAP = \(45^o\) => It is a 454590 triangle => AP = PC = AC/\(\sqrt{2}\) = \(x/\sqrt{2}\) => BP = \(x  x/\sqrt{2}\) In right triangle ABP: \(AB^2 = AP^2 + BP^2\) => \(2 = (x/\sqrt{2})^2 + (x  x/\sqrt{2})^2\) => \(2 = x^2/2 + x^2 + x^2/2  2x^2/\sqrt{2}\) => \(2 = x^2 * (2  \sqrt{2})\) => \(x^2 = 2/(2  \sqrt{2}) = ~ 2/0.6 = 3.33\) (approximately) => \(x = \sqrt{3.33} = 1.8\)=> Closest value = 2 Answer B\(√3.33\) = \(1.43\) 1.43 is closed to \(√3\). So the correct choice is C, actually. How is \(√3.33\) = \(1.43\)? \(1.4^2 = 1.96\) \(1.5^2 = 2.25\) \(1.8^2 = 3.24\)
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Re: In the diagram to the below, the value of x is closest to which of the
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11 Mar 2020, 14:12
IMO ans is 1
Its an iso . triangle bcoz it has 2 equal sides. One of the angle is 45 so the other one is also 45( same sides) Its a 45 45 90 triangle. The sides of 45 45 90 triangles are in ratio of 1 1 root 2. Hypo is root 2 therefore x is 1
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In the diagram to the below, the value of x is closest to which of the
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11 Mar 2020, 15:55
sujoykrdatta wrote: Asad wrote: In the diagram to the below, the value of \(x\) is closest to which of the following?
A) \(2+√2\) B) \(2\) C) \(√3\) D) \(√2\) E) \(1\) Let us drawn AP perpendicular to BC as shown below: Attachment: 111.JPG In triangle APC: Angle ACP = Angle CAP = \(45^o\) => It is a 454590 triangle => AP = PC = AC/\(\sqrt{2}\) = \(x/\sqrt{2}\) => BP = \(x  x/\sqrt{2}\) In right triangle ABP: \(AB^2 = AP^2 + BP^2\) => \(2 = (x/\sqrt{2})^2 + (x  x/\sqrt{2})^2\) => \(2 = x^2/2 + x^2 + x^2/2  2x^2/\sqrt{2}\) => \(2 = x^2 * (2  \sqrt{2})\) => \(x^2 = 2/(2  \sqrt{2}) = ~ 2/0.6 = 3.33\) (approximately) => \(x = \sqrt{3.33} = 1.8\) => Closest value = 2 Answer BHi sir, I think its closer to \(\sqrt{3}\). \(\sqrt{3}\)=1.7. Your answer is 1.8. It is closer to 1.7 than 2. Anyways my working is as follows  \(2 = (\frac{x}{\sqrt{2}})^2 + (x  \frac{x}{\sqrt{2}})^2\) \(or, 2 = 2x^2 \frac{2x^2}{\sqrt{2}}\) \(or, 1 = x^2  \frac{x^2}{\sqrt{2}}\) \(or, x^2 = \frac{\sqrt{2}}{(\sqrt{2}1)}\) \(or, x^2 = 1.4/0.4 = 3 (approx)\) \(or, x = \sqrt{3}\)



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Re: In the diagram to the below, the value of x is closest to which of the
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11 Mar 2020, 17:47
AnirudhaS wrote: sujoykrdatta wrote: Asad wrote: In the diagram to the below, the value of \(x\) is closest to which of the following?
A) \(2+√2\) B) \(2\) C) \(√3\) D) \(√2\) E) \(1\) Let us drawn AP perpendicular to BC as shown below: Attachment: 111.JPG In triangle APC: Angle ACP = Angle CAP = \(45^o\) => It is a 454590 triangle => AP = PC = AC/\(\sqrt{2}\) = \(x/\sqrt{2}\) => BP = \(x  x/\sqrt{2}\) In right triangle ABP: \(AB^2 = AP^2 + BP^2\) => \(2 = (x/\sqrt{2})^2 + (x  x/\sqrt{2})^2\) => \(2 = x^2/2 + x^2 + x^2/2  2x^2/\sqrt{2}\) => \(2 = x^2 * (2  \sqrt{2})\) => \(x^2 = 2/(2  \sqrt{2}) = ~ 2/0.6 = 3.33\) (approximately) => \(x = \sqrt{3.33} = 1.8\) => Closest value = 2 Answer BHi sir, I think its closer to \(\sqrt{3}\). \(\sqrt{3}\)=1.7. Your answer is 1.8. It is closer to 1.7 than 2. Anyways my working is as follows  \(2 = (\frac{x}{\sqrt{2}})^2 + (x  \frac{x}{\sqrt{2}})^2\) \(or, 2 = 2x^2 \frac{2x^2}{\sqrt{2}}\) \(or, 1 = x^2  \frac{x^2}{\sqrt{2}}\) \(or, x^2 = \frac{\sqrt{2}}{(\sqrt{2}1)}\) \(or, x^2 = 1.4/0.4 = 3 (approx)\) \(or, x = \sqrt{3}\) Yes obviously I don't know what came of me Must have not seen that option of root3 at all!  corrected that  thanks Posted from my mobile device
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Re: In the diagram to the below, the value of x is closest to which of the
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11 Mar 2020, 18:44
sujoykrdatta wrote: Asad wrote: sujoykrdatta wrote: Let us drawn AP perpendicular to BC as shown below: Attachment: 111.JPG In triangle APC: Angle ACP = Angle CAP = \(45^o\) => It is a 454590 triangle => AP = PC = AC/\(\sqrt{2}\) = \(x/\sqrt{2}\) => BP = \(x  x/\sqrt{2}\) In right triangle ABP: \(AB^2 = AP^2 + BP^2\) => \(2 = (x/\sqrt{2})^2 + (x  x/\sqrt{2})^2\) => \(2 = x^2/2 + x^2 + x^2/2  2x^2/\sqrt{2}\) => \(2 = x^2 * (2  \sqrt{2})\) => \(x^2 = 2/(2  \sqrt{2}) = ~ 2/0.6 = 3.33\) (approximately) => \(x = \sqrt{3.33} = 1.8\)=> Closest value = 2 Answer B\(√3.33\) = \(1.43\) 1.43 is closed to \(√3\). So the correct choice is C, actually. How is \(√3.33\) = \(1.43\)? \(1.4^2 = 1.96\) \(1.5^2 = 2.25\) \(1.8^2 = 3.24\) My calculator gave me wrong info (value of root 3.33). I was convinced with that wrong value (1.43) because i already know that the correct choice is C. Edited the first comment.. Posted from my mobile device



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Re: In the diagram to the below, the value of x is closest to which of the
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29 Mar 2020, 06:15
I do not understand this question. When x and x are the same lengths, their respective angles have to have the same degree, right ? so i do not understand how anyonecan say this is a 45  45  90 triangle. If this was true root 2 has to be the longest side, so that the angles of 45 and 45 are respective to the two x.
In this case side root 2 faces the angle 45 so the angles for x are 135/2, so you can not use the pythagorean theorem to calculate the sides?




Re: In the diagram to the below, the value of x is closest to which of the
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29 Mar 2020, 06:15




