Bunuel wrote:
In the equation \(x^2 + bx + 7= 0\), where x is a variable, and b is a constant. What is the value of b?
(1) x can take only positive integer values
(2) b is a negative integer
Are You Up For the Challenge: 700 Level Questions Analyzing the Question:If we have an equation in the form \(x^2 + ax + b= 0\), a is the negative sum of the two roots and b is the product of the two roots. So for \(x^2 + bx + 7= 0\) if we declare the two roots and m and n we have \(m*n = 7\) and \(m + n = -b\).
Statement 1:m and n are positive, therefore -b must be positive and b must be negative. Insufficient.
Statement 2:Insufficient.
Combined:We have duplicate information, we can automatically choose E. Besides m = 1 and n = 7 we can also have m = 0.5, n = 14, or m = n = sqrt(7) etc so there are multiple values of b we can take.
Statement A says postive integer value; can we use m = 0.5, n = 14 is it correct ? i think the answer is C