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In the figure above, is CD > BC ?

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In the figure above, is CD > BC ?  [#permalink]

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New post Updated on: 15 May 2017, 04:31
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A
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D
E

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In the figure above, is CD > BC ?

(1) AD = 20
(2) AB = CD

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Originally posted by mihir0710 on 15 May 2017, 01:04.
Last edited by Bunuel on 15 May 2017, 04:31, edited 2 times in total.
Edited the question.
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Re: In the figure above, is CD > BC ?  [#permalink]

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New post 15 May 2017, 01:35
Its straight E
AB=4 CD=4 BC=12
Answer is No
AB=8 CD=8 BC=4
Answer is No
E
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Re: In the figure above, is CD > BC ?  [#permalink]

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New post 15 May 2017, 02:07
Even if we combine both the statements, we can not infer whether CD > BC because:

Let AB = CD = x
AD = 20
Hence, 2x+BC = 20
or BC = 20- 2x

We are asked to determine if CD > BC which implies if x> 20-2x
or 3x> 20
or x> 20/3 ?
And we do not know the value of x.
Hence, Statement 1 and 2 together also are insufficient to answer the question.
Ans E
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Re: In the figure above, is CD > BC ?  [#permalink]

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New post 29 Jul 2017, 22:00
Let AB =x BC=y and CD=z therefore AD =x+y+z and the question stem is , IS z>y? from statement 1 x+y+z=20 hence we dont know the individual values NS. statement 2 say that x=z but there are no numerical values NS. 1+2 together 2z+y=20 and we cannot find the individual values, Hence E. Let me know if my method is correct. Thank you
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Re: In the figure above, is CD > BC ?   [#permalink] 29 Jul 2017, 22:00
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In the figure above, is CD > BC ?

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