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In the figure above, is CD > BC ?
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Updated on: 15 May 2017, 04:31
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91% (01:09) correct 9% (02:00) wrong based on 116 sessions
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In the figure above, is CD > BC ? (1) AD = 20 (2) AB = CD
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Originally posted by mihir0710 on 15 May 2017, 01:04.
Last edited by Bunuel on 15 May 2017, 04:31, edited 2 times in total.
Edited the question.



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Re: In the figure above, is CD > BC ?
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15 May 2017, 01:35
Its straight E AB=4 CD=4 BC=12 Answer is No AB=8 CD=8 BC=4 Answer is No E



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Re: In the figure above, is CD > BC ?
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15 May 2017, 02:07
Even if we combine both the statements, we can not infer whether CD > BC because:
Let AB = CD = x AD = 20 Hence, 2x+BC = 20 or BC = 20 2x
We are asked to determine if CD > BC which implies if x> 202x or 3x> 20 or x> 20/3 ? And we do not know the value of x. Hence, Statement 1 and 2 together also are insufficient to answer the question. Ans E



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Re: In the figure above, is CD > BC ?
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29 Jul 2017, 22:00
Let AB =x BC=y and CD=z therefore AD =x+y+z and the question stem is , IS z>y? from statement 1 x+y+z=20 hence we dont know the individual values NS. statement 2 say that x=z but there are no numerical values NS. 1+2 together 2z+y=20 and we cannot find the individual values, Hence E. Let me know if my method is correct. Thank you




Re: In the figure above, is CD > BC ?
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29 Jul 2017, 22:00






