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In the figure above, is CD > BC ?
[#permalink]
Updated on: 15 May 2017, 04:31
Updated on: 15 May 2017, 04:31
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A
B
C
D
E
Difficulty:
5%
(low)
Question Stats:
92% (01:04) correct
8%
(01:21)
wrong
based on 805
sessions
Attachment:
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(1) AD = 20
(2) AB = CD
Re: In the figure above, is CD > BC ?
[#permalink]
15 May 2017, 01:35
15 May 2017, 01:35
1
Kudos
Its straight E
AB=4 CD=4 BC=12
Answer is No
AB=8 CD=8 BC=4
Answer is No
E
AB=4 CD=4 BC=12
Answer is No
AB=8 CD=8 BC=4
Answer is No
E
Re: In the figure above, is CD > BC ?
[#permalink]
15 May 2017, 02:07
15 May 2017, 02:07
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Even if we combine both the statements, we can not infer whether CD > BC because:
Let AB = CD = x
AD = 20
Hence, 2x+BC = 20
or BC = 20- 2x
We are asked to determine if CD > BC which implies if x> 20-2x
or 3x> 20
or x> 20/3 ?
And we do not know the value of x.
Hence, Statement 1 and 2 together also are insufficient to answer the question.
Ans E
Let AB = CD = x
AD = 20
Hence, 2x+BC = 20
or BC = 20- 2x
We are asked to determine if CD > BC which implies if x> 20-2x
or 3x> 20
or x> 20/3 ?
And we do not know the value of x.
Hence, Statement 1 and 2 together also are insufficient to answer the question.
Ans E
