Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Dec 1511:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease.
Dec 1608:00 AM PST
-11:59 PM PST
GMAT Club 12 Days of Christmas is a 4th Annual GMAT Club Winter Competition based on solving questions. This is the Winter GMAT competition on GMAT Club with an amazing opportunity to win over $40,000 worth of prizes!- Dec 17
09:00 AM PST
-10:00 AM PST
Join Manhattan Prep instructor Whitney Garner for a fun—and thorough—review of logic-based (non-math) problems, with a particular emphasis on Data Sufficiency and Two-Parts. - Dec 18
10:00 AM PST
-11:00 AM PST
Here is the essential guide to securing scholarships as an MBA student! In this video, we explore the various types of scholarships available, including need-based and merit-based options.
29 Apr 2016, 04:02
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
59% (01:29) correct
41%
(02:01)
wrong
based on 94
sessions
History
Date
Time
Result
Not Attempted Yet
29 Apr 2016, 05:52
Kudos
Bookmarks
Is a^3 + b^5 > c^4?
(1) a < b < c
Scenario 1: let a=1/2, b=1 and c=2
-----------> (1/2)^3 + (1^5 > 2^4
-----------> 1/8 + 1 > 16 FALSE
Scenario 2: let a=2, b=3 and c=4
-----------> 2^3 + 3^5 > 4^4
-----------> 1944 > 256 TRUE
Statement 1 alone is not sufficient (cross out A and D)
(2) b < 0
The only thin we can conclude from this statement is that b^5 is negative since the -ve number b is raised to an odd exponent 5.
No info about a or c
Statement 2 alone is not sufficient (cross out B as well A and D)
Both statements together:
-----------> b<0 => a<0 and c>0
-----------> for any values of a and b, the a^3 + b^5 is -ve becuase both a and b are -ve numbers raised to odd exponents
-----------> c>0 so c^4 is positive
The final answer a^3 + b^5 IS NOT LESS THAN c^4
====> the answer is "C"
(1) a < b < c
Scenario 1: let a=1/2, b=1 and c=2
-----------> (1/2)^3 + (1^5 > 2^4
-----------> 1/8 + 1 > 16 FALSE
Scenario 2: let a=2, b=3 and c=4
-----------> 2^3 + 3^5 > 4^4
-----------> 1944 > 256 TRUE
Statement 1 alone is not sufficient (cross out A and D)
(2) b < 0
The only thin we can conclude from this statement is that b^5 is negative since the -ve number b is raised to an odd exponent 5.
No info about a or c
Statement 2 alone is not sufficient (cross out B as well A and D)
Both statements together:
-----------> b<0 => a<0 and c>0
-----------> for any values of a and b, the a^3 + b^5 is -ve becuase both a and b are -ve numbers raised to odd exponents
-----------> c>0 so c^4 is positive
The final answer a^3 + b^5 IS NOT LESS THAN c^4
====> the answer is "C"
nipunjain14
Joined: 07 May 2015
Last visit: 12 Aug 2017
Posts: 159
Own Kudos:
Given Kudos: 21
Location: India
Schools: ISB '19 Kellogg '20 Yale '20 HEC Dec"18
GMAT 1: 660 Q48 V31
GPA: 3
29 Apr 2016, 12:13
Kudos
Bookmarks
deabas
Is a^3 + b^5 > c^4?
(1) a < b < c
Scenario 1: let a=1/2, b=1 and c=2
-----------> (1/2)^3 + (1^5 > 2^4
-----------> 1/8 + 1 > 16 FALSE
Scenario 2: let a=2, b=3 and c=4
-----------> 2^3 + 3^5 > 4^4
-----------> 1944 > 256 TRUE
Statement 1 alone is not sufficient (cross out A and D)
(2) b < 0
The only thin we can conclude from this statement is that b^5 is negative since the -ve number b is raised to an odd exponent 5.
No info about a or c
Statement 2 alone is not sufficient (cross out B as well A and D)
Both statements together:
-----------> b<0 => a<0 and c>0
-----------> for any values of a and b, the a^3 + b^5 is -ve becuase both a and b are -ve numbers raised to odd exponents
-----------> c>0 so c^4 is positive
The final answer a^3 + b^5 IS NOT LESS THAN c^4
====> the answer is "C"
(1) a < b < c
Scenario 1: let a=1/2, b=1 and c=2
-----------> (1/2)^3 + (1^5 > 2^4
-----------> 1/8 + 1 > 16 FALSE
Scenario 2: let a=2, b=3 and c=4
-----------> 2^3 + 3^5 > 4^4
-----------> 1944 > 256 TRUE
Statement 1 alone is not sufficient (cross out A and D)
(2) b < 0
The only thin we can conclude from this statement is that b^5 is negative since the -ve number b is raised to an odd exponent 5.
No info about a or c
Statement 2 alone is not sufficient (cross out B as well A and D)
Both statements together:
-----------> b<0 => a<0 and c>0
-----------> for any values of a and b, the a^3 + b^5 is -ve becuase both a and b are -ve numbers raised to odd exponents
-----------> c>0 so c^4 is positive
The final answer a^3 + b^5 IS NOT LESS THAN c^4
====> the answer is "C"
2^3 + 3^5 > 4^4 = 8+243>256 = > 251>256 False
