stne wrote:
AsadAbu wrote:
Is \(|x|<6?\)
1) \((x+6)(x-6)≤0\)
2) \((x-6)(x-9)≤0\)
The answer seems to be D
Unless I am missing something both the statements do seem to contradict each other.
Statement 1 . -6<x<6 , so Yes |x| < 6
Statement 2: 6<x<9 So a definite NO |x| \(\nless\) 6
Here's what you are missing. (X+6)(x-6) <=0
X can be equal to -6 or can be equal to +6.. in these cases your answer would be definite no because |X| = 6
Now take this case of (x-6)(X+6) < 0
X-6<0 and X+6>0
-6<X<6
X can range from any values between 6 and -6.
Take X equals to 3...
|X| < 6 and your answer would be a definite yes....
Statement 1 is not sufficient on its own
Statement 2 :
If X = 9 and even if X= 6..
|X| < 6 , a definite no { (x-6)(x-9) = 0}
And 6>X>9 {(x-6)(x-9)<0
Take X as 7 |X| < 6, a definite no...
Statement 2 is sufficient on its own..
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