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M08-16

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Intern
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Re: M08-16 [#permalink]

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New post 01 Nov 2017, 07:23
I think this is a high-quality question and I agree with explanation.
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Re: M08-16 [#permalink]

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New post 09 Nov 2017, 00:51
Using the plug-in method is a faster way to get correct answer.

As we know that expression under square root is <=0, x must be <=2.

Plug in any value of x that is <=2, say x=1, in given expression​and each answer choice.

Only Choice A will match.

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Re: M08-16 [#permalink]

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New post 23 Nov 2017, 03:28
Bunuel wrote:
If each expression under the square root is greater than or equal to 0, what is \(\sqrt{x^2 - 6x + 9} + \sqrt{2 - x} + x - 3\)?

A. \(\sqrt{2 - x}\)
B. \(2x - 6 + \sqrt{2 - x}\)
C. \(\sqrt{2 - x} + x - 3\)
D. \(2x - 6 + \sqrt{x - 2}\)
E. \(x + \sqrt{x - 2}\)



Hie Bunuel,

Can you please provide link to similar kind of question
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Re: M08-16 [#permalink]

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New post 23 Nov 2017, 04:28
prk0789 wrote:
Bunuel wrote:
If each expression under the square root is greater than or equal to 0, what is \(\sqrt{x^2 - 6x + 9} + \sqrt{2 - x} + x - 3\)?

A. \(\sqrt{2 - x}\)
B. \(2x - 6 + \sqrt{2 - x}\)
C. \(\sqrt{2 - x} + x - 3\)
D. \(2x - 6 + \sqrt{x - 2}\)
E. \(x + \sqrt{x - 2}\)



Hie Bunuel,

Can you please provide link to similar kind of question



8. Exponents and Roots of Numbers



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Re: M08-16 [#permalink]

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New post 11 Feb 2018, 13:14
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I think this is a high-quality question and I agree with explanation. There is a grammar error on the explanation. Instead of "than" there should be "then" before ":"
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New post 11 Feb 2018, 20:49
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Re M08-16 [#permalink]

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New post 20 Feb 2018, 01:00
I think this is a high-quality question and I agree with explanation.
Re M08-16   [#permalink] 20 Feb 2018, 01:00

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