Forum Home > GMAT > Quantitative > Problem Solving (PS)
Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Dec 1608:00 AM PST
-11:59 PM PST
GMAT Club 12 Days of Christmas is a 4th Annual GMAT Club Winter Competition based on solving questions. This is the Winter GMAT competition on GMAT Club with an amazing opportunity to win over $40,000 worth of prizes!
Dec 1511:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease.- Dec 17
09:00 AM PST
-10:00 AM PST
Join Manhattan Prep instructor Whitney Garner for a fun—and thorough—review of logic-based (non-math) problems, with a particular emphasis on Data Sufficiency and Two-Parts. - Dec 18
10:00 AM PST
-11:00 AM PST
Here is the essential guide to securing scholarships as an MBA student! In this video, we explore the various types of scholarships available, including need-based and merit-based options. - Dec 21
11:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
71% (01:31) correct
29%
(01:30)
wrong
based on 119
sessions
History
Date
Time
Result
Not Attempted Yet
On the x-y coordinate grid, are points \(A (x_1, y_1\)) and \(B (x_2, y_2\)) equidistant from the origin?
(1) \(|x_1| = |y_1|\) for point A and \(|x_2| = |y_2|\) for point B
(2) \(|x_1|, |y_1|\) of point A = \(|x_2|, |y_2|\) of point B
@experts I really couldn't understand the explanation for this as below:
(1) \(|x_1| = |y_1|\) for point A and \(|x_2| = |y_2|\) for point B
(2) \(|x_1|, |y_1|\) of point A = \(|x_2|, |y_2|\) of point B
@experts I really couldn't understand the explanation for this as below:
The distance of a point from origin \(\sqrt{x^2 + y^2}\)
Therefore, to find the distance of a point from origin, we only need the absolute values of x and y co-ordinate of a point.
Therefore, to find the distance of a point from origin, we only need the absolute values of x and y co-ordinate of a point.
Shan2203
Joined: 07 Jan 2020
Last visit: 01 Feb 2021
Posts: 18
Own Kudos:
Given Kudos: 65
Location: India
Concentration: Technology, Economics
Schools: ISB'22 (A)
GMAT 1: 730 Q51 V37
GPA: 3.89
WE:Information Technology (Consulting)
14 Mar 2020, 11:51
Kudos
Bookmarks
(1) |x1| = |y1| for point A and |x2| = |y2| for point B --- Implies that x and y coordinates of A are equal , and similarly x and y coordinates of A are equal. Example A(3,3) and B(4,4) . Here A and B are not equidistant from the origin . But A can also be A(2,2) and B (2,2) which would prove that they are equidistant from origin -----Not Suff
(2) |x1|, |y1| of point A = |x2|, |y2| of point B --- Implies that since the coordinates of A and B are same , both the points are actually same. This means that they are at equal distance from origin -----Sufficient
Hence , ans is B
(2) |x1|, |y1| of point A = |x2|, |y2| of point B --- Implies that since the coordinates of A and B are same , both the points are actually same. This means that they are at equal distance from origin -----Sufficient
Hence , ans is B
shameekv1989
14 Mar 2020, 13:06
Kudos
Bookmarks
Kritisood
On the x-y coordinate grid, are points A (x1, y1) and B (x2, y2) equidistant from the origin?
(1) |x1| = |y1| for point A and |x2| = |y2| for point B
(2) |x1|, |y1| of point A = |x2|, |y2| of point B
@experts I really couldn't understand the explanation for this as below:
(1) |x1| = |y1| for point A and |x2| = |y2| for point B
(2) |x1|, |y1| of point A = |x2|, |y2| of point B
@experts I really couldn't understand the explanation for this as below:
The distance of a point from origin \sqrt{x^2 + y^2}
Therefore, to find the distance of a point from origin, we only need the absolute values of x and y co-ordinate of a point.
Therefore, to find the distance of a point from origin, we only need the absolute values of x and y co-ordinate of a point.
Distance of \(x_{1},y_1\) from Origin (0,0) is \(x_{1}^2+ y_1^2\)
Similarly, Distance of \(x_{2},y_2\) from Origin (0,0) is \(x_{2}^2+ y_2^2\)
So we are asked if \(x_{1}^2+ y_1^2\) = \(x_{2}^2+ y_2^2\)?
i) \(|x_1| = |y_1|\) => \(x_{1}^2 = y_1^2\)
\(|x_2| = |y_2|\) => \(x_{2}^2 = y_2^2\)
is \(2x_{1}^2\) = \(2x_{2}^2\) i.e. is \(|x_{1}| = |x_{2}|\)?- We don't know - Insufficient
ii) \(|x_1| = |x_2|\) => \(x_{1}^2 = x_2^2\)
\(|y_1| = |y_2|\) => \(y_{1}^2 = y_2^2\)
is \(x_{1}^2+ y_1^2\) = \(x_{2}^2+ y_2^2\)? => LHS = RHS - Sufficient
Answer - B
