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Re: Painters X and Y are simultaneously painting a house. If together the [#permalink]
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Bunuel wrote:
Painters X and Y are simultaneously painting a house. If together they can paint the house in 25 hours, how many more hours would it take painter X to paint the house if he worked alone?

(1) Painter X's rate is 4/5 that of painter Y.
(2) Painter Y could paint the house alone in 45 hours.


I hate actually doing the math on rates/work problems - it's tedious. I just approached this one intuitively. On rare occasion, doing this will lead you to the wrong answer, since there'll be some clever trick hidden in the problem. But 95% of the time it works and will save you some time.

In the question, there's one statement that relates painters X and Y: when they work together, they can paint one house in 25 hours. Presumably, this would translate to one equation that has an X and a Y in it (where X and Y stand for the rates of painters X and Y). I'm not going to worry about what that equation is, I'm just going to remember that it exists.

(1) This will also give you an equation that relates X and Y, and it's a different equation from the one given in the question. In this case, it's X = 4/5 Y. When you combine that with the equation from the question, you should be able to solve. Sufficient.

(2) Same reasoning as above. This gives you a second equation that tells you Y's rate. Plug that into the equation from the question and you'd be able to solve for X. Sufficient.

Now, I haven't even written out the equations to double check that everything works out how I think it will, but this is how I'd approach it on the test - and here, I trust that GMATPrepNow did the work correctly!
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Re: Painters X and Y are simultaneously painting a house. If together the [#permalink]
Bunuel wrote:
Painters X and Y are simultaneously painting a house. If together they can paint the house in 25 hours, how many more hours would it take painter X to paint the house if he worked alone?

(1) Painter X's rate is 4/5 that of painter Y.
(2) Painter Y could paint the house alone in 45 hours.


Answer : D

from (2) we are given Painter Y's rate. So we can work out the rate of Painter X. From this we can work out the time it would take for Painter X to work alone.

similarly from (1) we are given Painter X's rate in terms of Painter Y. We thus have 2 equations in 2 unknowns (the other from the stem) and we can solve for Painter X and Painter Y rates. We can work out the time needed for Painter X alone.

With these types of questions I find it quickest to understand the methodology and avoid solving actual equations. Just make sure that whenever you get 2 equations in 2 unknowns that they are unique equations and not just the same equation after simplifying. Otherwise E would be the answer!
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Re: Painters X and Y are simultaneously painting a house. If together the [#permalink]
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