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Sam10smart
23 Nov 2019, 09:35
Kudos
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Hey Guys
What can be the quickest approach to this question:-
A bag contains 3 Blue 5 Green 4 yellow balls
3 balls are drawn at random without replacement. What is the probability that exactly 2 of the 3 balls will be Blue.?
The approach i used is very lengthy and I think not correct or advisable
I used 1-(Prob of All Blue + Prob of no Blue + Prob of One Green)
Thanks
Posted from my mobile device
What can be the quickest approach to this question:-
A bag contains 3 Blue 5 Green 4 yellow balls
3 balls are drawn at random without replacement. What is the probability that exactly 2 of the 3 balls will be Blue.?
The approach i used is very lengthy and I think not correct or advisable
I used 1-(Prob of All Blue + Prob of no Blue + Prob of One Green)
Thanks
Posted from my mobile device
23 Nov 2019, 22:38
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Bookmarks
Sam10smart
Hey Guys
What can be the quickest approach to this question:-
A bag contains 3 Blue 5 Green 4 yellow balls
3 balls are drawn at random without replacement. What is the probability that exactly 2 of the 3 balls will be Blue.?
The approach i used is very lengthy and I think not correct or advisable
I used 1-(Prob of All Blue + Prob of no Blue + Prob of One Green)
Thanks
Posted from my mobile device
What can be the quickest approach to this question:-
A bag contains 3 Blue 5 Green 4 yellow balls
3 balls are drawn at random without replacement. What is the probability that exactly 2 of the 3 balls will be Blue.?
The approach i used is very lengthy and I think not correct or advisable
I used 1-(Prob of All Blue + Prob of no Blue + Prob of One Green)
Thanks
Posted from my mobile device
The correct way would be
Ways in which 2 are blue 3C2 and the third could be any of 5+4 or 9..3C2*9C1=3*9=27
Total ways = (3+5+4)C3=12C3=12*11*10/3*2=220
Prob=27/220
Sam10smart
23 Nov 2019, 22:56
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chetan2u
Sam10smart
Hey Guys
What can be the quickest approach to this question:-
A bag contains 3 Blue 5 Green 4 yellow balls
3 balls are drawn at random without replacement. What is the probability that exactly 2 of the 3 balls will be Blue.?
The approach i used is very lengthy and I think not correct or advisable
I used 1-(Prob of All Blue + Prob of no Blue + Prob of One Green)
Thanks
Posted from my mobile device
What can be the quickest approach to this question:-
A bag contains 3 Blue 5 Green 4 yellow balls
3 balls are drawn at random without replacement. What is the probability that exactly 2 of the 3 balls will be Blue.?
The approach i used is very lengthy and I think not correct or advisable
I used 1-(Prob of All Blue + Prob of no Blue + Prob of One Green)
Thanks
Posted from my mobile device
The correct way would be
Ways in which 2 are blue 3C2 and the third could be any of 5+4 or 9..3C2*9C1=3*9=27
Total ways = (3+5+4)C3=12C3=12*11*10/3*2=220
Prob=27/220
Dear Sir
Thank you so much.
Can you also try and get the same result using my approach?
Thanks
