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PS Fractions #13 from section 24 out 21-30 PS set

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PS Fractions #13 from section 24 out 21-30 PS set [#permalink]

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New post 30 Nov 2008, 03:38
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Hello All,

Please help me with this problem. I've been trying to solve this forever :oops: . I'm so tempted to use the calculator but I know I can't.

13. Of the following sums, which is the greatest?

A) (1/sqrt2) + (1/sqrt3) + (1/sqrt4) + (1/sqrt5)

B) (1/2^2) + (1/3^2) + (1/4^2) + (1/5^2)

C) (1/2^2) + (1/2^3) + (1/2^4) + 1/2^5)

D) (1) - (1/2) + (1/3) - (1/4)

E) (1/2) + (1/3) + (1/4) + (1/5)

How would you solve this in less than 2 mins?

Thanks so much in advance!!!

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Re: PS Fractions #13 from section 24 out 21-30 PS set [#permalink]

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New post 30 Nov 2008, 04:04
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I'd do it by elimination:

13. Of the following sums, which is the greatest?
A) (1/sqrt2) + (1/sqrt3) + (1/sqrt4) + (1/sqrt5)
B) (1/2^2) + (1/3^2) + (1/4^2) + (1/5^2)....def less than choice E, so out
C) (1/2^2) + (1/2^3) + (1/2^4) + 1/2^5)....def less than choice E, so out
D) (1) - (1/2) + (1/3) - (1/4)
E) (1/2) + (1/3) + (1/4) + (1/5)...def less than choice A, so out (sqrt of a number will always be smaller than the number, and since its in the denominator, it makes the whole number larger)

That leaves A and D:
simplying them:
D) 1/2 + 1/12 = 7/12
A) sqrt2/2 + sqrt3/3 + sqrt4/4 + sqrt5/5 = (6sqrt2 + 4sqrt3 + 3sqrt4)/12 + sqrt5/5 => we can see its greater than D.

Hence, A

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Re: PS Fractions #13 from section 24 out 21-30 PS set [#permalink]

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New post 30 Nov 2008, 05:50
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Quote:
I'd do it by elimination:

13. Of the following sums, which is the greatest?
A) (1/sqrt2) + (1/sqrt3) + (1/sqrt4) + (1/sqrt5)
B) (1/2^2) + (1/3^2) + (1/4^2) + (1/5^2)....def less than choice E, so out
C) (1/2^2) + (1/2^3) + (1/2^4) + 1/2^5)....def less than choice E, so out
D) (1) - (1/2) + (1/3) - (1/4)
E) (1/2) + (1/3) + (1/4) + (1/5)...def less than choice A, so out (sqrt of a number will always be smaller than the number, and since its in the denominator, it makes the whole number larger)

That leaves A and D:
simplying them:
D) 1/2 + 1/12 = 7/12
A) sqrt2/2 + sqrt3/3 + sqrt4/4 + sqrt5/5 = (6sqrt2 + 4sqrt3 + 3sqrt4)/12 + sqrt5/5 => we can see its greater than D.

Hence, A


Agree with you, there may be no other way.. How can we do it in 2 min?

1) (about 30 sec) We should see the similiraty between answer choices, A,B,C and E all are sums of four numbers with 1 as a numerator and with different denominators. The largest of them has the least values of denominators and, therefore it's A.
2) (about 30 sec) D = 7/12
3) (max. 1 min) D = 7/12 = 1/2 + 1/12; A = 1/sqrt4 + (sum of 3 numbers) = 1/2 + sum of 3 numbers, that is obviously greater than 1/12.

So, A is the answer

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Re: PS Fractions #13 from section 24 out 21-30 PS set [#permalink]

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New post 30 Nov 2008, 05:57
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look at it this way:-
\(2^3 > 2^2 >2 > sqrt(2)\)

so \(1/sqrt(2) > 1/2 >1/2^2 > 1/2^3\)

hence we are only left with A and D.
clearly D<1<A.

HTH.

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Re: PS Fractions #13 from section 24 out 21-30 PS set [#permalink]

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New post 30 Nov 2008, 05:59
Thank you!! I got it now. I appreciate all your help. :-D
Twilight, Atletikos and Parsun84....you all rock!!
OA is A.

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Re: PS Fractions #13 from section 24 out 21-30 PS set   [#permalink] 30 Nov 2008, 05:59
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PS Fractions #13 from section 24 out 21-30 PS set

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