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Re: The Given figure is a sector of a Circle with Centre at point O [#permalink]
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jimmy02 wrote:
How can you say that "AO+OC = 13 (half of perimeter)"

I think the answer should be E
A & B are not sufficient
If we check both options

Perimeter of circle is 5pi
but perimeter of rectangle is 26 means we have three possibilities for length & breath i.e. (9,4), (8,5) or (7,6)
these 3 possibilities give AC as \sqrt{97}, \sqrt{89} or \sqrt{85}

hence perimeter will be different in all cases.

SO the answer is E

Jimmy

GMATinsight wrote:
Attachment:
Question.jpg
The Given figure is a sector of a Circle with Centre at point O and Radius OX and OY such that OX and OY are making 90 degrees at point O. If OABC is a rectangle then Find the Perimeter of Red Outlined part (i.e. Perimeter of AYBXCA)?

(1) Radius of the Circle is 10 cm

(2) Perimeter of Rectangle OABC = 26

Answer:
To be Updated after 2-3 replies ;)


1) From this statement we can find circumference of circle and by dividing this length on 4 receive length of arc YX
But we need to know about sides of rectangle
We know that diagonal of rectangle equal to radius = 10 but only from diagonal we can't calculate its sides.
Insufficient

2) This statement give us partial information about sides but we know nothing about circle
Insufficient


1+2) We can calculate circumference of 1/4 circle (because we know that radius = 10) = 2pi10/4=5pi
OY + OX = 20 (two radiuses)
AO+OC = 13 (half of perimeter)
AY+CX = 20 - 13 = 7
So perimeter of AYBXCA = 7 + 10 + 5pi

Sufficient
Answer is C


but perimeter of rectangle is 26 means we have three possibilities for length & breath i.e. (9,4), (8,5) or (7,6)

The Highlighted part which you mentioned in your previous post has posed two mistakes

1) Nowhere it is given that sides of the rectangle have Integer Length

2) You have Missed the fact that Both Diagonal of Rectangle are always equal and when you draw the second Diagonal OB then it will be same as Radius of the sector = 10 and AC = OB = 10


The Remaining Calculation is here.

We don't need the length of the sides of Rectangle as half the perimeter of Rectangle will be equal to (Length + width) of Rectangle = 26/2 = 13
and AY + CX = (OY + OX) - (OA+OC) = (10+10) - (Length+Width of rectangle) = 20 - 13 = 7

I hope it answers your query!
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Re: The Given figure is a sector of a Circle with Centre at point O [#permalink]
:oops: Got it

My mistake

Thanks a lot

Jimmy

GMATinsight wrote:
jimmy02 wrote:
How can you say that "AO+OC = 13 (half of perimeter)"

I think the answer should be E
A & B are not sufficient
If we check both options

Perimeter of circle is 5pi
but perimeter of rectangle is 26 means we have three possibilities for length & breath i.e. (9,4), (8,5) or (7,6)
these 3 possibilities give AC as \sqrt{97}, \sqrt{89} or \sqrt{85}

hence perimeter will be different in all cases.

SO the answer is E

Jimmy

GMATinsight wrote:
Attachment:
Question.jpg
The Given figure is a sector of a Circle with Centre at point O and Radius OX and OY such that OX and OY are making 90 degrees at point O. If OABC is a rectangle then Find the Perimeter of Red Outlined part (i.e. Perimeter of AYBXCA)?

(1) Radius of the Circle is 10 cm

(2) Perimeter of Rectangle OABC = 26

Answer:
To be Updated after 2-3 replies ;)


1) From this statement we can find circumference of circle and by dividing this length on 4 receive length of arc YX
But we need to know about sides of rectangle
We know that diagonal of rectangle equal to radius = 10 but only from diagonal we can't calculate its sides.
Insufficient

2) This statement give us partial information about sides but we know nothing about circle
Insufficient


1+2) We can calculate circumference of 1/4 circle (because we know that radius = 10) = 2pi10/4=5pi
OY + OX = 20 (two radiuses)
AO+OC = 13 (half of perimeter)
AY+CX = 20 - 13 = 7
So perimeter of AYBXCA = 7 + 10 + 5pi

Sufficient
Answer is C


but perimeter of rectangle is 26 means we have three possibilities for length & breath i.e. (9,4), (8,5) or (7,6)

The Highlighted part which you mentioned in your previous post has posed two mistakes

1) Nowhere it is given that sides of the rectangle have Integer Length

2) You have Missed the fact that Both Diagonal of Rectangle are always equal and when you draw the second Diagonal OB then it will be same as Radius of the sector = 10 and AC = OB = 10


The Remaining Calculation is here.

We don't need the length of the sides of Rectangle as half the perimeter of Rectangle will be equal to (Length + width) of Rectangle = 26/2 = 13
and AY + CX = (OY + OX) - (OA+OC) = (10+10) - (Length+Width of rectangle) = 20 - 13 = 7

I hope it answers your query!
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Re: The Given figure is a sector of a Circle with Centre at point O [#permalink]
Prompt analysis
Let radius be R, OA = aOC =b
Four segments are there AY = R-a, AC =R, XY = /2 x R, CY =R - b and a2 + b2 = R2

Superset
The value of the perimeter = AY + AC + CY + XY will be a real number.

Translation
In order to find the value of perimeter, we need:
1# exact value of three variables.
2# 3 equations to solve 3 variables.

Statement analysis

St 1: R = 10 and a^2 + b^2 = R^2. 3 variables, 2 equation. INSUFFICIENT as we don't have any idea about the a,b.
St 2: 2(a+b) = 26 or a +b =13 and a^2 + b^2 = R^2. 3 variables, 2 equation. INSUFFICIENT as we don't have any idea about the a,b and R.

St1 & St 2: R = 10, a +b =13 and a^2 + b^2 = R^2. 3 variable and 3 equations. SUFFICIENT.

Option C
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Re: The Given figure is a sector of a Circle with Centre at point O [#permalink]
GMATinsight wrote:
Attachment:
Question.jpg
The Given figure is a sector of a Circle with Centre at point O and Radius OX and OY such that OX and OY are making 90 degrees at point O. If OABC is a rectangle then Find the Perimeter of Red Outlined part (i.e. Perimeter of AYBXCA)?

(1) Radius of the Circle is 10 cm

(2) Perimeter of Rectangle OABC = 26



This is how I visualized the problem, we have an arc with center o. The perimeter of the arc can be found using the formula, 2Πr c/360. We need to calculate the perimeter of triangle and subtract it from the arc perimeter.

1) Statement 1 is insufficient as we cannot calculate the perimeter of the triangle.
2) Statement 2 has the perimeter of the rectangle. The area of each triangle inside perimeter will be half of the rectangle. However, this statement does not mention about arc. Insufficient.

Combining both the above statements, we can calculate the perimeter of arc and the triangle (perimeter / 2). C
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Re: The Given figure is a sector of a Circle with Centre at point O [#permalink]
Expert Reply
GMATinsight wrote:
Attachment:
Question.jpg
The Given figure is a sector of a Circle with Centre at point O and Radius OX and OY such that OX and OY are making 90 degrees at point O. If OABC is a rectangle then Find the Perimeter of Red Outlined part (i.e. Perimeter of AYBXCA)?

(1) Radius of the Circle is 10 cm

(2) Perimeter of Rectangle OABC = 26




Assume that \(r\) is the radius of the circle, \(a\) is the length of OA and \(c\) is the length of OC.
The perimeter of AYBXCA is AY + YB + BX + XC + CA.
Since AY = \(( r - a )\), YB + BX = \(\frac{2pi*r}{4}\), XC =\(( r - c )\) and CA = OB = \(r\), the perimeter AYBXCA is \(3r - ( a + c ) + \frac{pi * r}{2}\).
Thus, the question asks what the value of \(3r - ( a + c ) + \frac{pi * r}{2}\) is.

In addition, we have \(a^2 + c^2 = r^2\) from Pythagras' theorem.

Now, we have 3 variables ( \(a\), \(c\), and \(r\) ) and 1 equation ( \(a^2 + c^2 = r^2\) ), and so the difference of them is 2.
Hence the choice C is most likely the correct one.

We can translate the conditions to the mathematical expressions with equations as follows.

(1) \(r = 10\)
(2) \(2(a+b) = 26\) or \(a + b = 13\)

It is clear each condition alone is not sufficient.

Let's consider both conditions together.
The perimeter AYBXCA,
\(3r - ( a + c ) + \frac{pi * r}{2} = 30 - 13 + \frac{10 pi}{2} = 17 + 5 pi\)

Therefore, C is the correct answer as expected.
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Re: The Given figure is a sector of a Circle with Centre at point O [#permalink]
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