The y-intercept of line k is negative. If the slope of line k is also

Hi Pretz,

This question is all about basic line and "slope" rules. You can solve it with some drawings.

Here's what you need to know to handle it. From the prompt, we know:
1) Line K has a NEGATIVE Y-intercept. That means that the line crosses the Y-axis BENEATH the Origin.
2) Line K has a NEGATIVE slope. That means the line goes "down and to the right"

The question asks which of the 3 options could be the X-intercept, meaning "which of these points on the X-axis COULD the line potentially cross?" At this point, you can plot each point and see if you can create a line that fits all of the given information.

By doing 3 quick sketches, you'll find that the first line has a negative slope, the second line has an infinite/undefined slope (the line goes straight up) and the third line has a positive slope (it goes "up and to the right").

Final Answer:
GMAT assassins aren't born, they're made,
Rich

Answer is A
Y intercept is negative :- Line will cut Y lie below the X-axiz (x can be both + or -)
Slope is negative:- Line will come from top left to bottom right (x can again be + or -)
The only value of X that satisfy both constraint is a negative value of x ; hence A (I only) is the correct answer

Hi,

Slope = - (y/x) = -ve, as per qsn statement.
As y = -ve, and the slope is negative as well, we need to have x -ve too to maintain the conditions.

Only -4 satisfies.

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.