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The y-intercept of line k is negative. If the slope of line k is also

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The y-intercept of line k is negative. If the slope of line k is also  [#permalink]

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New post 01 Mar 2015, 21:11
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The y-intercept of line k is negative. If the slope of line k is also
negative, which of the following could be the x-intercept of line k?
I. -4
II. 0
III. 3

(A) I only
(B) II only
(C) III only
(D) I and II
(E) I and III

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Re: The y-intercept of line k is negative. If the slope of line k is also  [#permalink]

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New post 01 Mar 2015, 23:40
Pretz wrote:
The y-intercept of line k is negative. If the slope of line k is also
negative, which of the following could be the x-intercept of line k?
I. -4
II. 0
III. 3

(A) I only
(B) II only
(C) III only
(D) I and II
(E) I and III


hipretz,
since the slope is negative, the line is decreasing as it moves from left to right..
since y intercept is negative, that is below the origin..
it will intercept x on left side of origin, which will be negative...
only I is negative so ans A...
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Re: The y-intercept of line k is negative. If the slope of line k is also  [#permalink]

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New post 02 Mar 2015, 00:21
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Hi Pretz,

This question is all about basic line and "slope" rules. You can solve it with some drawings.

Here's what you need to know to handle it. From the prompt, we know:
1) Line K has a NEGATIVE Y-intercept. That means that the line crosses the Y-axis BENEATH the Origin.
2) Line K has a NEGATIVE slope. That means the line goes "down and to the right"

The question asks which of the 3 options could be the X-intercept, meaning "which of these points on the X-axis COULD the line potentially cross?" At this point, you can plot each point and see if you can create a line that fits all of the given information.

By doing 3 quick sketches, you'll find that the first line has a negative slope, the second line has an infinite/undefined slope (the line goes straight up) and the third line has a positive slope (it goes "up and to the right").

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Re: The y-intercept of line k is negative. If the slope of line k is also  [#permalink]

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New post 02 Mar 2015, 02:41
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Pretz wrote:
The y-intercept of line k is negative. If the slope of line k is also
negative, which of the following could be the x-intercept of line k?
I. -4
II. 0
III. 3

(A) I only
(B) II only
(C) III only
(D) I and II
(E) I and III



Simply use this concept to solve this in a few seconds:

Slope of a line = - (y intercept)/(x intercept)

We know this property intuitively (explained here: http://www.veritasprep.com/blog/2011/09 ... -vertices/) but we still don't use it! Mind you, it is very useful in quite a few questions.

You are given that y intercept is negative. For slope to be negative, y intercept/x intercept should be positive so x intercept should be also be negative to cancel out the negative of the y intercept.

Only I is negative so answer is (A)
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Re: The y-intercept of line k is negative. If the slope of line k is also  [#permalink]

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New post 14 Jul 2016, 04:53
Pretz wrote:
The y-intercept of line k is negative. If the slope of line k is also
negative, which of the following could be the x-intercept of line k?
I. -4
II. 0
III. 3

(A) I only
(B) II only
(C) III only
(D) I and II
(E) I and III


Answer is A
Y intercept is negative :- Line will cut Y lie below the X-axiz (x can be both + or -)
Slope is negative:- Line will come from top left to bottom right (x can again be + or -)
The only value of X that satisfy both constraint is a negative value of x ; hence A (I only) is the correct answer
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Re: The y-intercept of line k is negative. If the slope of line k is also  [#permalink]

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New post 25 Feb 2017, 23:29
Hi,

Slope = - (y/x) = -ve, as per qsn statement.
As y = -ve, and the slope is negative as well, we need to have x -ve too to maintain the conditions.

Only -4 satisfies.
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Re: The y-intercept of line k is negative. If the slope of line k is also  [#permalink]

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Re: The y-intercept of line k is negative. If the slope of line k is also   [#permalink] 17 Jul 2018, 21:17
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