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TheUltimateWinner
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What is the numerical value of Updated on: 10 Feb 2020, 11:07
Originally posted by TheUltimateWinner on 07 Feb 2020, 08:58.
Last edited by TheUltimateWinner on 10 Feb 2020, 11:07, edited 2 times in total.
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

95% (hard)

Question Stats:

15% (01:21) correct 85% (01:01) wrong based on 72 sessions

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What is the numerical value of

\(\frac{(a+b)^8(a-b)^5}{(a-b)^3(a+b)^6(a-b)^2}\)

(1) \(a + b = 12 \)
(2) \(a – b = 8\)
Source: Top one percent by Sandeep Gupta
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C
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Archit3110
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What is the numerical value of Updated on: 10 Feb 2020, 10:56
Originally posted by Archit3110 on 10 Feb 2020, 09:05.
Last edited by Archit3110 on 10 Feb 2020, 10:56, edited 1 time in total.
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simplify given expression \(\frac{(a+b)^8(a-b)^5}{(a-b)^3(a+b)^6(a-b)^2}\)

we get
( a+b)^2
#1
a+b=12 ; sufficient
#2
a-b=8 ; insufficient
IMO A

Bunuel please check OA Asad
Asad
What is the numerical value of

\(\frac{(a+b)^8(a-b)^5}{(a-b)^3(a+b)^6(a-b)^2}\)

(1) \(a + b = 12 \)
(2) \(a – b = 8\)
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What is the numerical value of 10 Feb 2020, 10:33
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I got it as A as well. the whole expression can be reduced to \((a+b)^2\)

A gives the value and hence we have a numerical value of the expression.
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What is the numerical value of 10 Feb 2020, 11:09
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Archit3110
simplify given expression \(\frac{(a+b)^8(a-b)^5}{(a-b)^3(a+b)^6(a-b)^2}\)

we get
( a+b)^2
#1
a+b=12 ; sufficient
#2
a-b=8 ; insufficient
IMO A

Bunuel please check OA Asad
Asad
What is the numerical value of

\(\frac{(a+b)^8(a-b)^5}{(a-b)^3(a+b)^6(a-b)^2}\)

(1) \(a + b = 12 \)
(2) \(a – b = 8\)
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My Source says it is C.
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What is the numerical value of 11 Feb 2020, 00:45
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Archit3110
simplify given expression \(\frac{(a+b)^8(a-b)^5}{(a-b)^3(a+b)^6(a-b)^2}\)

we get
( a+b)^2
#1
a+b=12 ; sufficient
#2
a-b=8 ; insufficient
IMO A

Bunuel please check OA Asad
Asad
What is the numerical value of

\(\frac{(a+b)^8(a-b)^5}{(a-b)^3(a+b)^6(a-b)^2}\)

(1) \(a + b = 12 \)
(2) \(a – b = 8\)
Show more

The OA is correct. (1) is not sufficient because a - b could be 0, and in this case you cannot reduce by it and the whole expression becomes undefined: \(\frac{(a+b)^8(a-b)^5}{(a-b)^3(a+b)^6(a-b)^2}=0/0=undefined\). Not sure though that you'll get such question on the real test.
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What is the numerical value of 11 Feb 2020, 03:23
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Bunuel
Archit3110
simplify given expression \(\frac{(a+b)^8(a-b)^5}{(a-b)^3(a+b)^6(a-b)^2}\)

we get
( a+b)^2
#1
a+b=12 ; sufficient
#2
a-b=8 ; insufficient
IMO A

Bunuel please check OA Asad
Asad
What is the numerical value of

\(\frac{(a+b)^8(a-b)^5}{(a-b)^3(a+b)^6(a-b)^2}\)

(1) \(a + b = 12 \)
(2) \(a – b = 8\)

The OA is correct. (1) is not sufficient because a - b could be 0, and in this case you cannot reduce by it and the whole expression becomes undefined: \(\frac{(a+b)^8(a-b)^5}{(a-b)^3(a+b)^6(a-b)^2}=0/0=undefined\). Not sure though that you'll get such question on the real test.
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Thanks for the clarification Bunuel
But we still get 0/0 if we combine both statements. Is not it?
--> \(\frac{(a+b)^8(a-b)^5}{(a-b)^3(a+b)^6(a-b)^2}\)
--> \(\frac{(a+b)^8(a-b)^5}{(a+b)^6(a-b)^5}\)
--> \(\frac{(a+b)^8}{(a+b)^6} × \frac{(a-b)^5}{(a-b)^5}\)
--> \(\frac{(a+b)^8}{(a+b)^6} × \frac{0}{0}\)
--> \(\frac{(a+b)^8}{(a+b)^6} × undefined\)
Am I missing anything?
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What is the numerical value of 11 Feb 2020, 03:28
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Thanks for the clarification Bunuel
But we still get 0/0 if we combine both statements. Is not it?
--> \(\frac{(a+b)^8(a-b)^5}{(a-b)^3(a+b)^6(a-b)^2}\)
--> \(\frac{(a+b)^8(a-b)^5}{(a+b)^6(a-b)^5}\)
--> \(\frac{(a+b)^8}{(a+b)^6} × \frac{(a-b)^5}{(a-b)^5}\)
--> \(\frac{(a+b)^8}{(a+b)^6} × \frac{0}{0}\)
--> \(\frac{(a+b)^8}{(a+b)^6} × undefined\)
Am I missing anything?
Show more

\(\frac{(a-b)^5}{(a-b)^5}=\frac{0}{0}=undefined\) if a - b = 0 but since (2) says that a - b = 8, then \(\frac{(a-b)^5}{(a-b)^5}=1\), not 0/0.
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What is the numerical value of 11 Feb 2020, 03:43
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Bunuel
Asad
Thanks for the clarification Bunuel
But we still get 0/0 if we combine both statements. Is not it?
--> \(\frac{(a+b)^8(a-b)^5}{(a-b)^3(a+b)^6(a-b)^2}\)
--> \(\frac{(a+b)^8(a-b)^5}{(a+b)^6(a-b)^5}\)
--> \(\frac{(a+b)^8}{(a+b)^6} × \frac{(a-b)^5}{(a-b)^5}\)
--> \(\frac{(a+b)^8}{(a+b)^6} × \frac{0}{0}\)
--> \(\frac{(a+b)^8}{(a+b)^6} × undefined\)
Am I missing anything?

\(\frac{(a-b)^5}{(a-b)^5}=\frac{0}{0}=undefined\) if a - b = 0 but since (2) says that a - b = 8, then \(\frac{(a-b)^5}{(a-b)^5}=1\), not 0/0.
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Oh, sorry. I forgot to use the statement 2!
Thanks anyway...
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What is the numerical value of 05 Aug 2022, 09:34
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