This is a good example of a problem where
multiple approaches work well to solve. 1. Reasoning approach: Note that the answer choices share a remarkable similarity: they all contain an \(\frac{S}{2}\) term, which would represent the average of the two numbers. Since the two numbers differ by 2, one number must be 1 below the average and the other must be 1 above the average. Thus, the greater number is the average plus 1, or \(\frac{S}{2} + 1\) (choice D).
2. Picking numbers approach: Pick two easy numbers that differ by 2. Let’s pick 3 and 5. Thus, S = 8. Now plug 8 in for S in the answer choices to see which results in the greater of the two numbers, 5:
(A) S/2 - 1 --> 8/2 – 1 = 3
(B) S/2 --> 8/2 = 4
(C) S/2 + 1/2 --> 8/2 + 1/2 = 9/2
(D) S/2 + 1 --> 8/2 + 1 = 5
(E) S/2 + 2 --> 8/2 + 2 = 6
Only choice D results in 5, so it’s correct.
3. Algebraic approach: Let’s call the greater number x and the smaller number x – 2. Now let’s build an equation and solve for x:
x + (x – 2) = S
Since S is the sum of the two numbers.2x – 2 = S
Combine like terms.2x = S + 2
Add 2 to both sides.x = S/2 + 1
Divide both sides by 2. This is answer choice D.If you can see it, the reasoning approach is the fastest and cleanest here, and you should always be looking for reasoning approaches. But the picking numbers and algebraic approaches are also both reasonably fast.
It’s important to stay flexible and be comfortable with many approaches. That way, if you can’t see how to solve any particular problem one way, or if your chosen method ends up being unworkable, you can quickly shift to another.