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9А^2=12A+96
Then, we decompose 96 into 4 and -100 to make a quadratic equation
(9A^2)-12A+4-100=0
((3A-2)^2)-10^2=0
As we know, that: a^2-b^2=(a-b)(a+b),
(3A-2-10)(3A-2+10)=0
(3A-12)(3A+8)=0
A=4; A=-(8/3)
As A is a positive integer, we choose A=4

The same thing we do with the second equation f(B)
We get B=3

Then we just put our resulted A and B into our main equation:
5A+7B=(5*4)+(7*3)=20+21=41
Option C

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