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Bunuel
\((2^8)^{(2^3)}=\)

A. 2^11

B. 2^16

C. 2^48

D. 2^64

E. 2^72

First Simplify \(2^3\)=8,

(a^b)^c =a^bc

Hence 2^(8*8)=2^64

D
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Bunuel
\((2^8)^{(2^3)}=\)

A. 2^11

B. 2^16

C. 2^48

D. 2^64

E. 2^72


\((2^8)^{(2^3)}\)

= \((2^8)^{8}\)

= \(2^{64}\)

Answer will be (D) \(2^{64}\)
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( (x)^m)^n = x^(m*n)

Sent from my MotoG3 using GMAT Club Forum mobile app
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(2^8)^(2^3)
= \((2^{8})^{(2^{3})}\)
=\((2^{8})^{8}\)
=\(2^{8*8}\)
=\(2^{64}\)

Answer D
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