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Bunuel
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KetakiUpadhye
sumitkrocks
EB is the diameter of the circle with center O (Say)
Angle AEO and Angle ABO will be 45degrees each
Joining EO, DO and CO will give three Equilateral triangles {Measure of arc= Measure of central angle by the arc = half of inscribed angle}

Angle x = Angle ABO + Angle OBC = 45 + 60 = 105 Degrees

Option (B) is the correct choice IMO

Bunuel

In the polygon inscribed in circle O above, ∠A=90°. If AB=AE and BC=CD=DE, as shown above, what is the value of x?

A. 100
B. 105
C. 115
D. 120
E. 150



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Hi Sumit can you please explain the part of the equilateral triangle again. Thanks

Posted from my mobile device




Hi
the basic principle of a circle

equal chords subtend equal angles at the center, No matter their relative position with the center of the circle


SO angle subtended by DE,DC & CB at center are same and their total equals 180 degree so each of them equals 60 degree

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