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What is 363^(1/2) + 147^(1/2) + 27^(1/2)

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What is 363^(1/2) + 147^(1/2) + 27^(1/2)  [#permalink]

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New post 25 Apr 2017, 01:35
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

95% (01:15) correct 5% (01:41) wrong based on 132 sessions

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Re: What is 363^(1/2) + 147^(1/2) + 27^(1/2)  [#permalink]

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New post 25 Apr 2017, 02:18
root(363) = 11 * root (3)
root (147) = 7 * root (3)
root (27) = 3 * root (3)

adding them, we get 21 root(3)

Hence, D will be the answer.
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What is 363^(1/2) + 147^(1/2) + 27^(1/2)  [#permalink]

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New post 27 Apr 2017, 11:34
\(\sqrt{{363}} +\sqrt{{147}} + \sqrt{{27}}\)

363 = 11*11*3
147 = 7*7*3
27 = 3*3*3

= \(11\sqrt{{3}} + 7\sqrt{{3}} + 3\sqrt{{3}}\)

= \(21\sqrt{{3}}\)

Ans : Option D
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Re: What is 363^(1/2) + 147^(1/2) + 27^(1/2)  [#permalink]

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New post 27 Apr 2017, 12:42
363- Square root of 3 * Square root of 121 - 11 root 3
147- Square root of 49 * Square root of 3 - 7 root 3
27- Square root of 9 * Square root of 3 - 3 root 3

Add of these up (11 root 3 + 7 root 3 + 3 root 3) and we will get 21 root 3; Hence D
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Re: What is 363^(1/2) + 147^(1/2) + 27^(1/2)  [#permalink]

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New post 27 Apr 2017, 20:00
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Re: What is 363^(1/2) + 147^(1/2) + 27^(1/2)  [#permalink]

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New post 28 Apr 2017, 14:18
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Bunuel wrote:
What is \(\sqrt{363} + \sqrt{147}+ \sqrt{27}\)


A. \(6\sqrt{6}\)

B. \(7\sqrt{6}\)

C. \(11\sqrt{3}\)

D. \(21\sqrt{3}\)

E. \(30\sqrt{3}\)


Let’s simplify each root:

√363 = √121 x √3 = 11√3

√147 = √49 x √3 = 7√3

√27 = √9 x √3 = 3√3

Thus, we have:

11√3 + 7√3 + 3√3 = 21√3

Answer: D
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Re: What is 363^(1/2) + 147^(1/2) + 27^(1/2)  [#permalink]

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New post 22 Mar 2018, 23:37
Bunuel wrote:
What is \(\sqrt{363} + \sqrt{147}+ \sqrt{27}\)


A. \(6\sqrt{6}\)

B. \(7\sqrt{6}\)

C. \(11\sqrt{3}\)

D. \(21\sqrt{3}\)

E. \(30\sqrt{3}\)


\(\sqrt{363} + \sqrt{147}+ \sqrt{27}\)

\(\sqrt{11*11*3 + 7*7*3 + 3*3*3}\)

\(11*\sqrt{3} + 7*\sqrt{3} + 3*\sqrt{3}\)

\(21*\sqrt{3}\)

(D)
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Re: What is 363^(1/2) + 147^(1/2) + 27^(1/2) &nbs [#permalink] 22 Mar 2018, 23:37
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