SOLUTION
We are given:
• Two numbers, \(3x\) and \(4y\).
We need to find:
• Arithmetic mean of \(3x\) and \(4y\).
o Thus, we need to find the value of \(\frac{(3x + 4y)}{2}\).
Let us analyze both the statements one by one.
Statement-1: \(\frac{y}{6}\)-\(\frac{x}{8}\)=\(\frac{2}{3}\)Simplifying the above equation, we can write:
• \(\frac{(8y-6x)}{48}\)=\(\frac{2}{3}\)
• \(\frac{(4y-3x)}{16}\)=\(1\)
• \(4y-3x\)=\(16\)
Since we cannot find the value of \((3x+4y)\) from the above expression, hence statement 1 is not sufficient to answer the question.
Statement-2: \(\frac{y}{6}\) + \(\frac{x}{8}\) = \(\frac{5}{3}\)Simplifying the above equation, we can write:
• \(\frac{(8y+6x)}{48}\)=\(\frac{2}{3}\)
• \(\frac{(4y+3x)}{16}\)=\(1\)
• \(4y+3x\)=\(16\)
Since we are getting a unique value of \(4y+3x\). Hence, we can easily find the value of \(\frac{(4y+3x)}{2}\) from this information.
Therefore, Statement 2 ALONE is sufficient to answer the question.Answer: B