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21 Oct 2018, 21:53
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What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3x − 1?
A. 2x + 4
B. 3x − 2
C. 3x + 2
D. 4x − 2
E. 4x + 2
A. 2x + 4
B. 3x − 2
C. 3x + 2
D. 4x − 2
E. 4x + 2
21 Oct 2018, 21:58
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Bunuel
What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3x − 1?
A. 2x + 4
B. 3x − 2
C. 3x + 2
D. 4x − 2
E. 4x + 2
A. 2x + 4
B. 3x − 2
C. 3x + 2
D. 4x − 2
E. 4x + 2
Add 'x' terms and \(x^0\) terms , and divide by number of numbers( here 4),
Average or AM=\(\frac{2x+5x+6x+3x+3-4-6-1}{4}=\frac{16x-8}{4}=4x-2\)
Ans. (D)
SSwami
Joined: 08 Jan 2017
Last visit: 18 Jul 2020
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Location: India
Schools: NUS '21 McCombs '21 Desautels '21
GMAT 1: 630 Q45 V31
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22 Oct 2018, 06:54
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Average/Mean = (Sum of all the terms)/ (No of the terms)
Here,
Sum of all the terms= (2x + 3) + (5x − 4) + (6x − 6) + (3x − 1)
= 16x - 8
No of the terms = 4
Average = (16x - 8)/ 4
= 4x - 2(D)
Here,
Sum of all the terms= (2x + 3) + (5x − 4) + (6x − 6) + (3x − 1)
= 16x - 8
No of the terms = 4
Average = (16x - 8)/ 4
= 4x - 2(D)
