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# What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3

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Math Expert
Joined: 02 Sep 2009
Posts: 50711
What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3  [#permalink]

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21 Oct 2018, 20:53
00:00

Difficulty:

15% (low)

Question Stats:

91% (00:32) correct 9% (00:25) wrong based on 34 sessions

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What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3x − 1?

A. 2x + 4

B. 3x − 2

C. 3x + 2

D. 4x − 2

E. 4x + 2

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WE: Supply Chain Management (Energy and Utilities)
What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3  [#permalink]

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21 Oct 2018, 20:58
Bunuel wrote:
What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3x − 1?

A. 2x + 4

B. 3x − 2

C. 3x + 2

D. 4x − 2

E. 4x + 2

Add 'x' terms and $$x^0$$ terms , and divide by number of numbers( here 4),

Average or AM=$$\frac{2x+5x+6x+3x+3-4-6-1}{4}=\frac{16x-8}{4}=4x-2$$

Ans. (D)
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Joined: 08 Jan 2017
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Re: What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3  [#permalink]

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22 Oct 2018, 05:54
Average/Mean = (Sum of all the terms)/ (No of the terms)

Here,
Sum of all the terms= (2x + 3) + (5x − 4) + (6x − 6) + (3x − 1)
= 16x - 8
No of the terms = 4

Average = (16x - 8)/ 4
= 4x - 2(D)
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Re: What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3  [#permalink]

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23 Oct 2018, 18:26
Bunuel wrote:
What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3x − 1?

A. 2x + 4

B. 3x − 2

C. 3x + 2

D. 4x − 2

E. 4x + 2

(2x + 3 + 5x − 4 + 6x − 6 + 3x − 1)/4 = (16x - 8)/4 = 4x - 2

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Re: What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3 &nbs [#permalink] 23 Oct 2018, 18:26
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