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# What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3

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What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3  [#permalink]

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21 Oct 2018, 21:53
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Difficulty:

5% (low)

Question Stats:

94% (00:44) correct 6% (00:38) wrong based on 44 sessions

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What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3x − 1?

A. 2x + 4

B. 3x − 2

C. 3x + 2

D. 4x − 2

E. 4x + 2

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What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3  [#permalink]

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21 Oct 2018, 21:58
Bunuel wrote:
What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3x − 1?

A. 2x + 4

B. 3x − 2

C. 3x + 2

D. 4x − 2

E. 4x + 2

Add 'x' terms and $$x^0$$ terms , and divide by number of numbers( here 4),

Average or AM=$$\frac{2x+5x+6x+3x+3-4-6-1}{4}=\frac{16x-8}{4}=4x-2$$

Ans. (D)
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Re: What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3  [#permalink]

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22 Oct 2018, 06:54
Average/Mean = (Sum of all the terms)/ (No of the terms)

Here,
Sum of all the terms= (2x + 3) + (5x − 4) + (6x − 6) + (3x − 1)
= 16x - 8
No of the terms = 4

Average = (16x - 8)/ 4
= 4x - 2(D)
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Re: What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3  [#permalink]

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23 Oct 2018, 19:26
Bunuel wrote:
What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3x − 1?

A. 2x + 4

B. 3x − 2

C. 3x + 2

D. 4x − 2

E. 4x + 2

(2x + 3 + 5x − 4 + 6x − 6 + 3x − 1)/4 = (16x - 8)/4 = 4x - 2

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Re: What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3   [#permalink] 23 Oct 2018, 19:26
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# What is the average (arithmetic mean) of 2x + 3, 5x − 4, 6x − 6, and 3

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