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# What is the average (arithmetic mean) of a, b, c, d, e, and f with a <

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Re: What is the average (arithmetic mean) of a, b, c, d, e, and f with a < [#permalink]
Bunuel wrote:
What is the average (arithmetic mean) of a, b, c, d, e, and f with a < b < c < d < e < f ?

(1) The average of d, e, and f is 11.
(2) The value of a is 5 and b + c + d + e + f = 51.

PS21260

Statement 1: The average of d, e, and f is 11.

Now we are given: a<b<c. The combination for them could be anything: a = 1, b=2, c = 3, or a= -3, b = -2 , c = -1. Since, we are not given the nature of the number, we have a wide range of possibilities.

Thus Insufficient.

Statement 2: (2) The value of a is 5 and b + c + d + e + f = 51.
Now,
a = 5,
b + c + d + e + f = 51.
=> a+ b + c + d + e + f = 56 = > average = 56/6.

Thus we have the average from this statement.
So Sufficient.

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Re: What is the average (arithmetic mean) of a, b, c, d, e, and f with a < [#permalink]
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Bunuel wrote:
What is the average (arithmetic mean) of a, b, c, d, e, and f with a < b < c < d < e < f ?

(1) The average of d, e, and f is 11.
(2) The value of a is 5 and b + c + d + e + f = 51.
DS21260

Target question: What is the average (arithmetic mean) of a, b, c, d, e, and f

Statement 1: The average of d, e, and f is 11.
We can take this information and write: (d + e + f)/3 = 11, which means d + e + f = 33.
However, since we have no information about the value of a, b and c, there's no way to find the average of a, b, c, d, e, and f
Since we can't answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: The value of a is 5 and b + c + d + e + f = 51.
Average of the 6 values = (a + b + c + d + e + f)/6
Substitute given values: = (5 +51)/6
Simplify: = 56/6
Since we can answer the target question with certainty, statement 2 is SUFFICIENT