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10 Mar 2016, 05:03
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E
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Difficulty:
15%
(low)
Question Stats:
80% (01:32) correct
20%
(01:22)
wrong
based on 249
sessions
History
Date
Time
Result
Not Attempted Yet
What is the product of all positive factors of 18?
A. 39
B. 324
C. 1521
D. 3042
E. 5832
A. 39
B. 324
C. 1521
D. 3042
E. 5832
livio04
Joined: 21 Nov 2014
Last visit: 25 Nov 2016
Posts: 22
Own Kudos:
Given Kudos: 5
Location: United States
Concentration: Marketing, Social Entrepreneurship
Schools: HEC '18 (A) INSEAD Jan '17 Bocconi '17 IE
GPA: 3.55
WE:Brand Management (Consumer Packaged Goods)
10 Mar 2016, 05:12
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Positive factors of 18 are 1,2,3,6,9, and 18. The factors set up 3 pairs of 18 (18*1, 2*9, 3*6), hence its product is 18^3, which is 5832. I would go for E, then.
10 Mar 2016, 05:56
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Prime Factorization of 18 = 2^1 * 3^2
Therefore number of factors of 18 = (1+1)*(2+1) = 6 = say A
{factors of 18 are (1,18) , (2,9) , (3,6) i.e 6 in number}
Now product of all factors of 18 = 18^(A/2) = 18^(6/2) = 18^3 = 5832 (Answer is E)
Therefore number of factors of 18 = (1+1)*(2+1) = 6 = say A
{factors of 18 are (1,18) , (2,9) , (3,6) i.e 6 in number}
Now product of all factors of 18 = 18^(A/2) = 18^(6/2) = 18^3 = 5832 (Answer is E)
