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X persons stand on the circumference of a circle at distinct points.

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X persons stand on the circumference of a circle at distinct points.  [#permalink]

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New post Updated on: 10 Aug 2018, 00:34
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X persons stand on the circumference of a circle at distinct points. Each possible pair of persons, not standing next to each other, sings a two-minute song one pair after the other. If the total time taken for singing is 28 minutes, what is X?

(a) 5
(b) 7
(c) 9
(d) 4
(e) 11

Originally posted by Bulusuchaitanya on 09 Aug 2018, 08:20.
Last edited by Bunuel on 10 Aug 2018, 00:34, edited 1 time in total.
Renamed the topic.
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Re: X persons stand on the circumference of a circle at distinct points.  [#permalink]

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New post 17 Aug 2018, 11:24
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Bulusuchaitanya wrote:
X persons stand on the circumference of a circle at distinct points. Each possible pair of persons, not standing next to each other, sings a two-minute song one pair after the other. If the total time taken for singing is 28 minutes, what is X?

(a) 5
(b) 7
(c) 9
(d) 4
(e) 11



A way to look at it..
When you join these X person, a polygon is formed. And as we do not count the neighbors, it is basically asking us to find DIAGONAL..
Number of diagonals = X(x-3)/2=28/2....X(X-3)=28=7*4..
Thus X is 7

another way...
A person cannot make pair with himself and his neighbours so 3 out of X gone..
So he can make pair with X-3 person..
Thus total X*X-3 but this includes where each combination is counted twice A with C as a different way from C with A..
So total =X(X-3)/2
Total minutes=28, so pairs = 28/2=14..
Thus X (X-3)/2=14....X(X-3)=28=7*4
X=7
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Re: X persons stand on the circumference of a circle at distinct points.  [#permalink]

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New post 09 Aug 2018, 09:25
What is the number of pairs here?

According to me it is X(X-3): [Rationale: X-3 as we substract possible number of pairants by selecting any one, and not consider the other 2 people next to him on either side; X as that is the total number of starting persons we can repeat this exercise with]

In this case my equation comes: X(X-3)*2 = 28

And X is not any of the answers. Can someone help me by pointing out where I went wrong.
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Re: X persons stand on the circumference of a circle at distinct points.  [#permalink]

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New post 09 Aug 2018, 09:36
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mitrakaushi wrote:
What is the number of pairs here?

According to me it is X(X-3): [Rationale: X-3 as we substract possible number of pairants by selecting any one, and not consider the other 2 people next to him on either side; X as that is the total number of starting persons we can repeat this exercise with]

In this case my equation comes: X(X-3)*2 = 28

And X is not any of the answers. Can someone help me by pointing out where I went wrong.



So Each pair is getting calculated twice in your Equation. You may have to divide the Equation with 2.
then the equation becomes x(x-3)= 28
and the answer you get is 7


Now what I really dont know is if this is a Hard question or a medium level question.
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X persons stand on the circumference of a circle at distinct points.  [#permalink]

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New post 17 Aug 2018, 09:27
Hi guys anyone can explain this better i'm struggling to answer it,nor am i able to understand the formula's posted above.
Any experts able to throw some light.
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X persons stand on the circumference of a circle at distinct points.  [#permalink]

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New post 17 Aug 2018, 10:35
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Avinasht123 wrote:
Hi guys anyone can explain this better i'm struggling to answer it,nor am i able to understand the formula's posted above.
Any experts able to throw some light.


Avinasht123
I am not expert, I can try to explain

Let there be \(n\) person standing in a circle. Then we have to form teams with 2 people each, such that these 2 people selected in a team should not be adjacent to each other in the circle.

For first person , we can \(n\) choices, we can select anybody out of \(n\) persons.

For second person, we have \(n-3\) [\(n- 1\)(person already selected)\(-1\)(Person to the right of already selected person)\(-1\)(Person to the left of already selected person)]

Total number of such 2 person team:\(\frac{n(n-3)}{2}\)

Division by \(2\) is required as expression \(n(n-3)\) counts AB,BA as two pairs , whereas they are only one pair

Now Question says each team formed should sing a 2 minute song.

Total time spent by \(\frac{n(n-3)}{2}\) teams singing=\(2* \frac{n(n-3)}{2}\)minutes

Now in question , it is given that \(n(n-3)=28\)
This leads to \(n(n-3)=28\)
\(n^2-3n-28=0\)
\(n^2-7n+4n-28=0\)
\(n(n-7)+4(n-7)=0\)
\((n+4)(n-7)=0\)
\(n=7\) neglecting \(n=-4\)
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X persons stand on the circumference of a circle at distinct points.  [#permalink]

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New post 20 Aug 2018, 07:26
Bismark thank you very much for the explanation are you sure you are not an expert ;)
Chetan2u thanks a ton.
X persons stand on the circumference of a circle at distinct points. &nbs [#permalink] 20 Aug 2018, 07:26
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