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# Math Revolution and GMAT Club Contest! x + y = ?

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Math Revolution and GMAT Club Contest! x + y = ?  [#permalink]

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12 Dec 2015, 08:51
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Math Revolution and GMAT Club Contest Starts!

QUESTION #9:

x + y = ?

(1) $$y = 2x - 1$$
(2) $$y^2 = -|1 - 2x|$$

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Re: Math Revolution and GMAT Club Contest! x + y = ?  [#permalink]

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12 Dec 2015, 09:23
8
x + y = ?

(1) y=2x−1. Clearly insufficient.

(2) y^2=−|1−2x|. y^2 cannot be negative but it can be zero. So y^2 = 0 or y = 0. So |1−2x| is 0. or x = 1/2. So x+y = 1/2. Sufficient.

Ans. B
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Re: Math Revolution and GMAT Club Contest! x + y = ?  [#permalink]

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12 Dec 2015, 10:19
1
QUESTION #9:

x + y = ?

(1) y=2x−1
(2) y2=−|1−2x|

(1) : y = 2x - 1 : no additional information to identify the combination of x+y or to solve individually for x or y. clearly insufficient.
(2) y^2 = -|1-2x|
y^2 is clearly always >=0 ;
since all absolutes are always >=0 ; it follows that |1-2x| >=0 and therefore -|1-2x| is less than equal to zero
Given the constraints on both left hand side and right hand side of the equation -- y^2 >=0 and -|1-2x| <=0 .. it follows that only one value is possible for both the sides , that is both are equal to 0.

so y^2 = 0 and y = 0;
similarily -|1-2x| = 0 => 1-2x = 0 => x = 1/2
so x+y = 1/2 (unique answer) -- hence sufficient.

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Re: Math Revolution and GMAT Club Contest! x + y = ?  [#permalink]

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12 Dec 2015, 10:30
Guys,

The first statement doesnt give us any value for x+y and the 2nd statement is against the math basics being that the absolute value of (1-2x) is always positive for all x and y^2 cannot be a negative number so answer is E right?
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Re: Math Revolution and GMAT Club Contest! x + y = ?  [#permalink]

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12 Dec 2015, 11:20
I picked E, although i have my doubts.

x + y = ?

(1) y=2x−1
knowing this, we have x+2x-1 = 3x-1, not sufficient.

(2) y^2=−|1−2x|
ok, how the hell can a squared number be negative? impossible.
let's multiply everything by -1.
-y^2 = |1-2x|
ok, now:
-y^2 = 1-2x or -y^2 = 2x-1

doesn't tell us much:

combine 1+2.

y=2x-1
-y^2 = either 1-2x or 2x-1.

square first equation to get 4x^2 - 4x + 1

now, negative of this, will equal either 1-2x or 2x-1, let's test both cases:
-(4x^2 - 4x + 1) = 1-2x
-4x^2 +4x - 1 = 1-2x
-4x^2 +6x -2 = 0 | divide everything by 2
-2x^2 +3x - 2 = 0
-2 = 2x^2 - 3x
-2 = x(2x-3)
doesn't tell much. so this should raise red flags that C is not sufficient.

-4x^2 +4x-1 = 2x-1
-4x^2 -2x=0
-4x^2 = 2x | divide by 2x
-2x = 1
x = -1/2
ok, now if x=-1/2, then y should be 0.

nevertheless, since 2 outcomes are possible. C is insufficient, and the answer is E.
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Re: Math Revolution and GMAT Club Contest! x + y = ?  [#permalink]

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12 Dec 2015, 15:29
1
We're asked whether, given the information in the two statements we can calculate the one value of x+y.

Statement 1) is obviously not sufficient to tie down $$x+y$$ as $$y$$ increases with $$x$$ and therefore $$x+y$$ can take an infinite number of values. For example if $$x=1$$, $$y=1$$, and $$x+y=2$$; and if $$x=2$$, $$y=3$$, and $$x+y=5$$. We have two different answers and therefore 1) is not sufficient.

Statement 2) is a little more complicated. We know that in GMAT no imaginary numbers are allowed, therefore a square number must not be $$<0$$, and the left hand side of the equation is $$>=0$$. The right hand side of the equation is a negative sign next to a modulus, and since a modulus is $$>=0$$, the negative of a modulus is $$<=0$$. The only value which each side of the equation can take is $$0$$, and this gives us $$y=0$$ and $$(1-2x)=0$$ which gives us $$x=1/2$$. Therefore statement 2) is sufficient and the answer is B.
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Re: Math Revolution and GMAT Club Contest! x + y = ?  [#permalink]

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12 Dec 2015, 18:39
Find x+y

1) y = 2x - 1 -> no way to find what x+y is. Insufficient

2) y^2 = -|1-2x| -> this can be written as follows.

y^2 = 2x-1 (x can be any positive integer greater than 0)
y^2 = 1-2x (x can be any negative integer <= 0)

In either case, we cannot find x+y.

1&2 together -

when y^2 = 2x-1 & y = 2x-1 -> (x, y) = (1/2, 0) or (1, 1)
when Y^2 = 1-2x & y=2x-1 -> (x, y) = (1/2, 0) or (0, -1)

here (1/2, 0) satisfies both forms of y^2 = -|1-2x|. Hence x+y - 1/2. or Answer is C
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Re: Math Revolution and GMAT Club Contest! x + y = ?  [#permalink]

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12 Dec 2015, 20:33
1
(1) Insufficient.
(2) $$y^2 = -|1-2x| => y = 0 & x = 1/2 => x+y = 1/2$$ Sufficient
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Re: Math Revolution and GMAT Club Contest! x + y = ?  [#permalink]

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13 Dec 2015, 02:50
1
x + y =?

St1: y = 2x−1
x = 1 --> y = 1 --> x + y = 2
x = 2 --> y = 3 --> x + y = 5
St1 does not result in a unique solution. So St1 is not sufficient.

St2: y^2 = -|1 - 2x|
x = 1 --> y^2 = -1 --> y^2 can never be negative. So this answer is not possible.
x = -1 --> y^2 = -3 --> Again it is not possible
x = 1/2 --> y^2 = 0 --> y = 0 --> Possible

Thus x = 1/2 and y = 0 --> x + y = 1/2
St2 is sufficient

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Re: Math Revolution and GMAT Club Contest! x + y = ?  [#permalink]

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13 Dec 2015, 05:40
1
x + y = ?

(1) y=2x−1
(2) y 2 =−|1−2x|
Solution-
1)y+x=3x-1 ,hence not sufficient.
2)y 2 =−|1−2x| -->y2=0 (since y2 can't be negative)-->1-2x=0--->x=1/2------>x+y=1/2 Hence sufficient.

Correct Choice-B
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Re: Math Revolution and GMAT Club Contest! x + y = ?  [#permalink]

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13 Dec 2015, 08:03
1
Statement 1: x+y=x+2x-1=3x-1, not suficient
Statement 2:Y^2=-mod(1-2x)
the only possibility is 1-2x should be 0 because square of a number cannot be negative
=>x=1/2, y=0, x+y=1/2, sufficient
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Re: Math Revolution and GMAT Club Contest! x + y = ?  [#permalink]

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13 Dec 2015, 10:08
2
With Just I, we have 1 equation and 2 variables. Hence Not Sufficient

with II, we can construct 2 equations for 2 variables
$$y^2 = 1 - 2x$$ and $$y^2 = 2x - 1$$
we can solve for x and y and find the value of x + y

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Re: Math Revolution and GMAT Club Contest! x + y = ?  [#permalink]

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13 Dec 2015, 10:09
2
With Just I, we have 1 equation and 2 variables. Hence Not Sufficient

with II, we can construct 2 equations for 2 variables
$$y^2 = 1 - 2x$$ and $$y^2 = 2x - 1$$
we can solve for x and y and find the value of x + y

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Re: Math Revolution and GMAT Club Contest! x + y = ?  [#permalink]

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13 Dec 2015, 22:27
1) y=2x-1

2) y^2= -|1-2x|

now x+y=?

1) insufficient

2) as LHS will always be positive, we can say |1-2x| will be positive , so its equal to (1-2x)

thus, y^2 = -( 1-2x)
y^2 = 2x-1

again In sufficient

1+2.. gives (1/2,0) and (1,1).. but not unique soln

Thus ans E
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Re: Math Revolution and GMAT Club Contest! x + y = ?  [#permalink]

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14 Dec 2015, 02:16
QUESTION #9:
x + y = ?

(1) y=2x−1
(2) y2=−|1−2x|

Solution:

Statement: (A): not sufficient
(B): Not Sufficient
H'ever, taking both the statements together we got:
y^2=−|1−2x|
or, y^2=-(1-2x)
or, (2x-1)^2=-1+2x
or, (2x-1)(2x-1)=2x-1
or, (2x-1)(2x-1)-(2x-1)=0
or, (2x-1)((2x-1-1)=0
so, 2x-1=0; 2x-1-1=0
so, x=1/2; x-1
so, x=1/2, 1

when x=1, y=(2x2)-1=3
when x=1/2, y=(2.1/2)-1=0

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Re: Math Revolution and GMAT Club Contest! x + y = ?  [#permalink]

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14 Dec 2015, 19:44
QUESTION #9:

x + y = ?

(1) $$y=2x−1$$
(2) $$y^2=−|1−2x|$$

(1) $$x+y=x+2x-1=3x-1$$ - unknown x --> insufficient
(2) $$y^2=−|1−2x|$$: can find x as function of $$y^2$$ and plug in $$x+y$$ but still y is unknown --> insufficient

(1) + (2):
$$y=2x-1$$ --> $$x=\frac{y+1}{2}$$ --> $$x+y= \frac{3y+1}{2}$$ (*)
$$y^2=−|1−2x|$$
When $$x =<1/2$$ --> $$y^2=2x−1$$ --> $$x = \frac{y^2+1}{2}$$ --> $$x+y=\frac{y^2+2y+1}{2}$$ (**)
from (*) and (**) --> $$\frac{3y+1}{2}=\frac{y^2+2y+1}{2}$$ --> $$y=0$$ or $$y=1$$ --> $$x+y$$ has 2 solution --> insufficient

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Re: Math Revolution and GMAT Club Contest! x + y = ?  [#permalink]

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14 Dec 2015, 23:32
2
from statement 1
y=2x-1. we cant find the values of x and y

from statement 2

y^2=-mod1-2x

square of any number is always>=0. of non negative.

mod always non negative. but statment mentions Y^2=-mod.
only Y=0 satisfy the equaiton so mod also 0.

so 1-2x=0, imply x=1/2.now we both values of x and y.
so option B is correct.
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Re: Math Revolution and GMAT Club Contest! x + y = ?  [#permalink]

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15 Dec 2015, 02:28
1) $$y=2x−1$$ ==> $$y^2 =(2x−1)^2$$ insufficient

2)$$y^2=−|1−2x| ==> y^2 = - 1 - 2x$$ or $$y^2 = 1 + 2x$$ insufficient

The two statments together:
Case 1
$$(2x−1)^2= - 1 - 2x$$
$$4x^2 - 4x+1=-1-2x$$
$$4x^2-2x+2=0$$
No solution for x, discriminant ($$b^2 -4ac < 0$$)

Case 2
$$(2x−1)^2= 1 + 2x$$
$$4x^2 - 6x=0$$
$$x(4x-6) =0$$
$$x = 0$$ or $$x =3/2$$

when $$x =0, y = -1 ==> x + y = -1$$
When $$x = 3/2, y = 2 ==> x + y = 7/2$$
We can't find a single result for the sum of x and y
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Re: Math Revolution and GMAT Club Contest! x + y = ?  [#permalink]

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16 Dec 2015, 12:36
1
$$x + y =_________ ?$$
We are asked to find the value of $$x + y$$.

Statement 1 : $$y = 2x − 1$$
--> $$y - 2x = - 1$$
There is no way this equation can be further modified to obtain the value of $$x + y$$.

Not Sufficient.

Statement 2 : $$y^2 = − | 1 − 2x |$$
First, look closely at each part of this equation.

We have $$y^2$$ on one side so we know that $$y^2$$ on is either equal to a positive number or equal to $$0$$.

We have $$− | 1 − 2x |$$ on the other side. $$| 1 − 2x |$$ is either equal to a positive number or to $$0$$. Therefore $$− | 1 − 2x |$$ will either be equal to a negative number or to $$0$$.
So the only way $$y^2$$ and $$− | 1 − 2x |$$ can be equal to each other is if they are both equal to 0.

$$y^2 =$$0 so $$y = 0$$. So you can solve the equation for x by plugging in the value of y. Once you will have done this, you will have the individual values of $$x$$ and $$y$$ and a fortiori the value of $$x + y$$ . Note that at this stage, you don't need to calculate any further since this is a DS question.
Just for the sake of completeness, here is the end of the explanation:
$$− | 1 − 2x | = 0$$ --> $$1 - 2x = 0$$ --> $$x = \frac{1}{2}$$
So $$x + y = \frac{1}{2}$$

Sufficient

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Re: Math Revolution and GMAT Club Contest! x + y = ?  [#permalink]

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17 Dec 2015, 05:27
1
Statement 2 is sufficient.

Statement 1- We are given nothing that will help us get to the values for x and y or rather x+y.
Statement 2- we are given that square of y is equal to a negative number. This is only possible if that number is zero. Thus, y=0 and 1-2x=0 . which implies x=1/2. Thus we can get x+y = 1/2.

So, the answer is statement 2 sufficient but statement 1 is not sufficient. => option B.
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Re: Math Revolution and GMAT Club Contest! x + y = ? &nbs [#permalink] 17 Dec 2015, 05:27

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