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13 Jul 2017, 21:46
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xy and yx are reversed 2 digit integers. y is even. If xy + 6x = yx + y^2, what is the sum of x and y?
A. 10
B. 11
C. 12
D. 15
E. 17
(source:self)
A. 10
B. 11
C. 12
D. 15
E. 17
(source:self)
13 Jul 2017, 22:22
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Looking at the eq :-
xy+6x=yx+y^2
X(Y+6) =Y(X+Y)
When Y is even = 0,2,4,8,6 is possible
When Y=0 => X(0+6)=0(X+0) 0. Not Possible
When Y=2 => X(2+6) =2(X+2) = 8X-2X=4, Not an option. Non Integer Output
When Y=4=> X(4+6)=4(X+4) = 10X=4X+16 .. Not an option. Non Integer Output
When Y=6=> x(6+6)=6(X+6)= 12x=6x+36, x=6,y=6 x+y = 6+6 =12 = > Option C
When Y=8=> X14=8(X+8) Not an option. Non Integer Output
Press kudos
Thanks,
xy+6x=yx+y^2
X(Y+6) =Y(X+Y)
When Y is even = 0,2,4,8,6 is possible
When Y=0 => X(0+6)=0(X+0) 0. Not Possible
When Y=2 => X(2+6) =2(X+2) = 8X-2X=4, Not an option. Non Integer Output
When Y=4=> X(4+6)=4(X+4) = 10X=4X+16 .. Not an option. Non Integer Output
When Y=6=> x(6+6)=6(X+6)= 12x=6x+36, x=6,y=6 x+y = 6+6 =12 = > Option C
When Y=8=> X14=8(X+8) Not an option. Non Integer Output
Press kudos
Thanks,
gracie
xy and yx are reversed 2 digit integers. y is even. If xy+6x=yx+y^2, what is the sum of x and y?
A. 10
B. 11
C. 12
D. 15
E. 17
(source:self)
A. 10
B. 11
C. 12
D. 15
E. 17
(source:self)
xy+6x=yx+y^2➡
10x+y+6x=10y+x+y^2➡
(y^2)/3+3y=5x
if y is even integer, only possible value of y=6
if y=6, then x=6 also
12
C
