1 + 1/(1 + 1/(1 + 1/3))

Question

1+\frac{1}{1+\frac{1}{1+\frac{1}{3}}}= A. 4/7 B. 4/3 C. 11/8 D. 11/7 E. 7/4 fraction.JPG

Bunuel · Answer

1+\frac{1}{1+\frac{1}{1+\frac{1}{3}}}=

A. 4/7

B. 4/3

C. 11/8

D. 11/7

E. 7/4

1+\frac{1}{1+\frac{1}{1+\frac{1}{3}}}=1+\frac{1}{1+\frac{1}{\frac{4}{3}}}=1+\frac{1}{1+\frac{3}{4}}=1+\frac{1}{\frac{7}{4}}=1+\frac{4}{7}=\frac{11}{7} .

Answer: D.

dave13 · Answer

Hi Bunuel , why did you move up one number "1" from denominator the denominator looks like this as it is in the picture --> 1+1 + \frac{1}{1+3} and denominator should equal 11/4 I got final answer 4/11

BrentGMATPrepNow · Answer

Aside: Bunuel is using a very useful (and often tested) fraction property that says: 1/(a/b) = b/a

Some examples: 
1/(2/3) = 3/2
1/(8/5) = 5/8

MORE USEFUL FRACTION PROPERTIES HERE: 
 https://www.youtube.com/watch?v=718lE2Hvlnk

NandishSS · Answer

dave13  He didn't move any denominator!!! He just simplified the denominator.

1+ \frac{1}{3}  = 4/3 & 1/(4/3)=3/4

ScottTargetTestPrep · Answer

Let’s first simplify 1 + 1/3:

1 + 1/3 = 4/3

1/(4/3) = 3/4. So we now have:

1 + 1/(1 + 3/4)

1 + 1/(7/4)

1 + 4/7 = 7/7 + 4/7 = 11/7

Answer: D

Probus · Answer

Hi  Bunuel ,

Can you edit this question. The way it is shown in image is

1 / {1+1+   }

And Also i tried to post it mathematically . But it wouldn't show up in the format . 
 
 \frac{1}{1+1 +   1/1+ 1/3}

Where am i going wrong
Probus

adstudy · Answer

Hi GMAT D11,

The question should be formatted like this to get OA as D.

1 +  \frac{1}{1+\frac{1}{1+\frac{1}{3}}}

If we frame it like the image in the question answer seems to round upto -

\frac{4}{11}

hasnain3047 · Answer

<img src="{SMILIES_PATH}/1f44d-1f3fb.png" class="forumSmileyItem" width="20" height="20" alt=":thumbup:" title="Thumbup" />

Kinshook · Answer

1+\frac{1}{1+\frac{1}{1+\frac{1}{3}}}=1+\frac{1}{1+\frac{3}{4}} = 1+\frac{4}{7} = \frac{11}{7}

IMO D

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1 + 1/(1 + 1/(1 + 1/3))

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1 + 1/(1 + 1/(1 + 1/3))

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