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1 + 1/(1 + 1/(1 + 1/3))

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1 + 1/(1 + 1/(1 + 1/3)) [#permalink]

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New post 13 Feb 2011, 06:45
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A
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D
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Difficulty:

  5% (low)

Question Stats:

82% (01:09) correct 18% (01:35) wrong based on 146 sessions

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fraction.JPG
fraction.JPG [ 28.33 KiB | Viewed 2609 times ]

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Re: 1 + 1/(1 + 1/(1 + 1/3)) [#permalink]

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New post 13 Feb 2011, 07:06
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1 + 1/(1 + 1/(1 + 1/3)) [#permalink]

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New post 24 Feb 2018, 12:24
Bunuel wrote:
\(1+\frac{1}{1+\frac{1}{1+\frac{1}{3}}}=1+\frac{1}{1+\frac{1}{\frac{4}{3}}}=1+\frac{1}{1+\frac{3}{4}}=1+\frac{1}{\frac{7}{4}}=1+\frac{4}{7}=\frac{11}{7}\).

Answer: D.



Hi Bunuel, why did you move up one number "1" from denominator

the denominator looks like this as it is in the picture --> 1+1+\(\frac{1}{1+3}\) and denominator should equal 11/4

I got final answer 4/11 :?
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Re: 1 + 1/(1 + 1/(1 + 1/3)) [#permalink]

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New post 24 Feb 2018, 14:48
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Aside: Bunuel is using a very useful (and often tested) fraction property that says: 1/(a/b) = b/a

Some examples:
1/(2/3) = 3/2
1/(8/5) = 5/8

MORE USEFUL FRACTION PROPERTIES HERE:

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Re: 1 + 1/(1 + 1/(1 + 1/3)) [#permalink]

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New post 25 Feb 2018, 19:08
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dave13 wrote:
Bunuel wrote:
\(1+\frac{1}{1+\frac{1}{1+\frac{1}{3}}}=1+\frac{1}{1+\frac{1}{\frac{4}{3}}}=1+\frac{1}{1+\frac{3}{4}}=1+\frac{1}{\frac{7}{4}}=1+\frac{4}{7}=\frac{11}{7}\).

Answer: D.



Hi Bunuel, why did you move up one number "1" from denominator

the denominator looks like this as it is in the picture --> 1+1+\(\frac{1}{1+3}\) and denominator should equal 11/4

I got final answer 4/11 :?


dave13 He didn't move any denominator!!! He just simplified the denominator.

1+\(\frac{1}{3}\) = 4/3 & 1/(4/3)=3/4
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Re: 1 + 1/(1 + 1/(1 + 1/3)) [#permalink]

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New post 28 Feb 2018, 11:25
GMATD11 wrote:
Attachment:
fraction.JPG


Let’s first simplify 1 + 1/3:

1 + 1/3 = 4/3

1/(4/3) = 3/4. So we now have:

1 + 1/(1 + 3/4)

1 + 1/(7/4)

1 + 4/7 = 7/7 + 4/7 = 11/7

Answer: D
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Re: 1 + 1/(1 + 1/(1 + 1/3))   [#permalink] 28 Feb 2018, 11:25
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