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22 Jul 2019, 01:32
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
88% (00:32) correct
12%
(01:09)
wrong
based on 60
sessions
History
Date
Time
Result
Not Attempted Yet
\(a \circ b = \frac{ab}{a+b}\) for all a, b that satisfy \(a ≠ -b\). What is the value of \((–4) \circ 2\)?
A. \(-4\)
B. \(-2\)
C. \(-\frac{4}{3}\)
D. \(\frac{4}{3}\)
E. \(4\)
A. \(-4\)
B. \(-2\)
C. \(-\frac{4}{3}\)
D. \(\frac{4}{3}\)
E. \(4\)
22 Jul 2019, 02:36
Kudos
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Bunuel
Given: \(a \circ b = \frac{ab}{a+b}\) for all a, b that satisfy \(a ≠ -b\).
Asked: What is the value of \((–4) \circ 2\)?
\((–4) \circ 2 = \frac{(-4)*2}{-4+2}= \frac{-8}{-2} = 4\)
IMO E
23 Jul 2019, 04:34
Kudos
Bookmarks
Solution
Given:
- • \(a ∘ b = \frac{ab}{a+b}\)
• a ≠ −b
To find:
- • The value of (–4)∘2
Approach and Working Out:
- • \((–4)∘2 = \frac{-4*2}{(-4 + 2)} = \frac{-8}{-2} = 4\)
Hence, the correct answer is Option E.
Answer: E
