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# A cafeteria served hamburgers and hot dogs on a certain day. If the co

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Math Expert
Joined: 02 Sep 2009
Posts: 54376
A cafeteria served hamburgers and hot dogs on a certain day. If the co  [#permalink]

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01 Aug 2017, 12:24
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Difficulty:

25% (medium)

Question Stats:

95% (01:27) correct 5% (00:52) wrong based on 31 sessions

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A cafeteria served hamburgers and hot dogs on a certain day. If the cost of each hamburger was \$5 and the cost of each hot dog was \$3, what was the total cost of the hamburgers and hot dogs served by the cafeteria that day?

(1) The total number of hamburgers and hot dogs served was 130.

(2) The ratio of the number of hamburgers to the number of hot dogs served was 3 to 2.

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Joined: 11 Jul 2016
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Location: India
Concentration: Technology, General Management
GMAT 1: 550 Q36 V30
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Re: A cafeteria served hamburgers and hot dogs on a certain day. If the co  [#permalink]

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01 Aug 2017, 12:47
Let, hamburger=x hotdogs=y
We have to find 5x+3y=?

Statement 1: x+y=130
Individually x and y can have infinite values to add upto 130.
Insufficient.

Statement 2: x/y=3/2. --> x=(3y)/2

Combining 1 and 2:
(3y)/2+ y=130
We get value of y and hence also value of x...finially giving the ultimate result for 5x+3y.

Ans: C
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Re: A cafeteria served hamburgers and hot dogs on a certain day. If the co  [#permalink]

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01 Aug 2017, 12:49

Simplifying the question stem gives us the following equation 5x +3y = ?. Where x is the number of hamburgers and y is the number of hot dogs. We need to find what "?" Is.

Statement 1 gives us the equation x+y=130 but this could mean x=100 and y=30 or x=30 and y=100, each of those gives us a different answer for "?" Therefore this statement is NOT SUFFICIENT

Statement 2 tells us that the Ham:Hot is 3:2, this again doesn't give us enough information since x could be 3 and y could be 2 or x=30 and y=20. Both of those would give different answers for "?" Therefore this statement is NOT SUFFICIENT

1+2, now that we know the total number of hamburgers and hamburgers and the ratio for each, we can find what x and y are since we can find the common multiplier for the ratio z. 3z + 2z = 5z => 5z = 130 => z=26. 3(26) = 78 hamburgers and 2(26) = 52 Hot dogs. Now we can find the total cost. Therefore these two statements together are sufficient
Re: A cafeteria served hamburgers and hot dogs on a certain day. If the co   [#permalink] 01 Aug 2017, 12:49
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