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Bunuel
A cube with a volume of 64 cubic inches is inscribed within a sphere such that all 8 vertices of the cube are on the sphere. What is the circumference of the sphere, in inches?

A. 2π√2
B. 2π√3
C. 4π√2
D. 4π√3
E. 8π√2

Since the cube is inscribed in the sphere, we know that the diagonal of the cube is equal to the diameter of the sphere.

Since the volume of the cube is 64 and volume = side^3, the side is 4. Since the diagonal of a cube is side√3, the diagonal of the cube is 4√3.

Since the sphere’s diameter = 4√3, its radius is 2√3, and thus its circumference = 2πr = 2π(2√3) = 4π√3.

Answer: D

Certainly so, here is how the figure will look -
Attachment:
main-qimg-4fa003c3a8c93fdbba78e63d8f8c4622.png
main-qimg-4fa003c3a8c93fdbba78e63d8f8c4622.png [ 8.09 KiB | Viewed 7253 times ]
Answer must be (D)
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Hi Bunuel,

Sphere is 3-D object, so will there be circumference for this object or is the question asking about the projection of the sphere?
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Picturing a Symmetric Cube Inscribed inside a Sphere, you can visualize that the Diameter of the Sphere that passes through the Center from Opposite Ends of the Sphere = Main Diagonal through the Center of the 3-D Cube


Volume of Cube = (s)^3 = 64

s = 4 = Edge of Cube

Main Diagonal of Cube = [ 4 * sqrt(2) ] ^2 + (4)^2 = (Main Diagonal)^2

d = sqrt(16 * 2 + 16)

d = 4 * sqrt(3)


d = Main Diagonal of Cube = Diameter of Sphere = 4 * sqrt(3)


the Circumference of a Sphere is given by: (pi) * (Diameter)

Circumference of Sphere = 4 * (pi) * sqrt(3)

-D-
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A cube with a volume of 64 cubic inches is inscribed within a sphere such that all 8 vertices of the cube are on the sphere. What is the circumference of the sphere, in inches?

Let the side of cube = a
Volume of the cube = \(a^3\)=64----> a =4

Longest side of a cube = Diameter of the sphere= \(\sqrt{3}*a\)= \(\sqrt{3}*4\)

Circumference of the sphere = 2πr= 2π* \(\sqrt{3}*2\)= 4π√3



A. 2π√2
B. 2π√3
C. 4π√2
D. 4π√3
E. 8π√2
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