Bunuel
A rectangular garden is surrounded by a 3 ft. wide concrete sidewalk. If the length of the garden is 4 ft more than its width, and if the area of the sidewalk is 60 sq ft more than the area of the garden, then what is the length of the garden?
A. 6
B. 8
C. 10
D. 12
E. 14
Kudos for a correct solution.
MAGOOSH OFFICIAL SOLUTION:This is a challenging geometry problem. Let the width of the garden be x, so the length is (x + 4). The garden itself would have an area of x(x + 4). Now, for the area of the sidewalk, consider this diagram:
Attachment:
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Notice, the sidewalk can be subdivided into convenient pieces. There are two of the long horizontal rectangles at the top and bottom; each is 3(x + 4). There are two vertical side rectangles: each is 3x. Finally, there are four corner squares, each 3 x 3 = 9. The total area of the sidewalk is:
area of sidewalk = 6(x + 4) + 6x + 4*9 = 12x + 24 + 36 = 12x + 60
Now, we are told that
(area of sidewalk) = (area of garden) + 60
12x + 60 = x(x + 4) + 60
12x = x^2 + 4x
0 = x^2 - 8x = x(x - 8)
The solution x = 0 doesn’t make sense in the problem, so the only solution this gives is x = 8. This means, the garden is 8 x 12, and the length of the garden is 12.
Answer = (D).