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In the figure, ABCD is a rectangle, and the area of triangle ACE is 10, what is the area of rectangle ?
A. 18
B. 22.5
C. 36
D. 54
E. 60
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28 Dec 2010, 07:07
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hirendhanak
In the figure, ABCD is a rectangle, and the area of triangle ACE is 10, what is the area of rectangle ?
A. 18
B. 22.5
C. 36
D. 54
E. 60
\(area_{ACE}=\frac{1}{2}*base*height=\frac{1}{2}*CE*AB=10\);
\(\frac{1}{2}*5*AB=10\);
\(AB=4\).
\(area_{ABCD}=AB*CB=AB*(CE+EB)=4*9=36\).
Answer: C.
28 Dec 2010, 08:23
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thanks bunuel
I was not clear why we took AB as the height of triangle ACE . because AB is out of scope of the triangle ACE.
I thought AE becomes height of the triangle ACE.
I was not clear why we took AB as the height of triangle ACE . because AB is out of scope of the triangle ACE.
I thought AE becomes height of the triangle ACE.
