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17 Aug 2019, 01:20
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Adam completes 60% of a task in 15 days and then takes the help of Bob and Carol. Bob is 50% as efficient as Adam is and Carol is 50% as efficient as Bob is. In how many more days will they complete the task?
A. \(13\frac{1}{3}\) days
B. \(8\frac{2}{3}\) days
C. \(5\frac{5}{7}\) days
D. \(7\frac{5}{7}\) days
E. 5 days
A. \(13\frac{1}{3}\) days
B. \(8\frac{2}{3}\) days
C. \(5\frac{5}{7}\) days
D. \(7\frac{5}{7}\) days
E. 5 days
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17 Aug 2019, 01:26
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Adam completes 60% of a task in 15 days and then takes the help of Bob and Carol. Bob is 50% as efficient as Adam is and Carol is 50% as efficient as Bob is. In how many more days will they complete the task?
A. \(13\frac{1}{3}\) days
B. \(8\frac{2}{3}\) days
C. \(5\frac{5}{7}\) days
D. \(7\frac{5}{7}\) days
E. 5 days
A. \(13\frac{1}{3}\) days
B. \(8\frac{2}{3}\) days
C. \(5\frac{5}{7}\) days
D. \(7\frac{5}{7}\) days
E. 5 days
Given: Adam completes 60% of a task in 15 days and then takes the help of Bob and Carol. Bob is 50% as efficient as Adam is and Carol is 50% as efficient as Bob is.
Asked: In how many more days will they complete the task?
Balance work = 40%
Adam completes 60% of a task in 15 days
Adam complete 100% of the task in 15*100/60 = 25 days
Bob is 50% as efficient as Adam is
Bob completes 100% of the task in 50 days.
and Carol is 50% as efficient as Bob is.
Carol completes 100% of the task in 100 days.
In how many more days will they complete the task =\(40\% / (\frac{1}{25} + \frac{1}{50} + \frac{1}{100}) = \frac{2}{5} * \frac{100}{7} = \frac{40}{7} = 5 \frac{5}{7}\) days
IMO C
17 Aug 2019, 02:58
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Adam completes rest of the work in 10 days.
0.6/15 =0.4/?, ?=10
So he completes 1/10 of work in one day.
Bob=1/2 *1/10=1/20
Carol=1/2 *1/20=1/40
(1/10+ 1/20+ 1/40)*X=1
X=40/7 = 5 5/7
Option C
Posted from my mobile device
0.6/15 =0.4/?, ?=10
So he completes 1/10 of work in one day.
Bob=1/2 *1/10=1/20
Carol=1/2 *1/20=1/40
(1/10+ 1/20+ 1/40)*X=1
X=40/7 = 5 5/7
Option C
Posted from my mobile device
