joseph0alexander wrote:
Bunuel wrote:
Set A consist of 10 terms, each of which is a reciprocal of a prime number, is the median of the set less than 1/5?
(1) Reciprocal of the median is a prime number.
(2) The product of any two terms of the set is a terminating decimal.
Hi again Bunuel!
This is how I am interpreting this question. Based on this interpretation when I read your explanation, I'm getting totally lost. Please help.
Prompt: A set consists of reciprocals of 10 different prime numbers (1/2, 1/3 ..... 1/101....). Is the sum of the 5 and 6th term less than 1.5?
Statement 1: Reciprocal of the average of the 5th and 6th term is also a prime number. I understand your explanation and this is clearly not sufficient.
Statement 2: 1/2 and 1/5 are the only numbers which are a part of this set (squares or cubes of these numbers also can't be a part of this set as the question states that the numbers are reciprocals of primes only).
The 10 numbers could be 9 1/2's and 1 1/5 as well. So we don't know have sufficiency?Is this understanding correct? IMHO answer is EFor (2) the set could be any combination of 1/2's and 1//5:
{1/2, 1/2, 1/2, 1/2, 1/2, 1/2, 1/2, 1/2, 1/2, 1/2}
{1/5, 1/5, 1/5, 1/5, 1/5, 1/5, 1/5, 1/5, 1/5, 1/5}
{1/5, 1/5, 1/5, 1/5, 1/5, 1/2, 1/2, 1/2, 1/2, 1/2}
....
Let me ask you: could the median of any of the sets above be less than 1/5?