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# Four containers of flour are on the table: The first contains 1/3 of a

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Joined: 02 Sep 2009
Posts: 53063
Four containers of flour are on the table: The first contains 1/3 of a  [#permalink]

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08 Feb 2019, 02:45
00:00

Difficulty:

25% (medium)

Question Stats:

80% (02:03) correct 20% (01:45) wrong based on 10 sessions

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Four containers of flour are on the table: The first contains 1/3 of a pound, the second contains 1/6 of a pound, the third contains 1/9 of a pound, and the fourth contains 1/18 of a pound. If each container can hold one pound of flour, how many additional pounds of flour are required to fill all four containers?

A. 2/9
B. 2/3
C. 11/9
D. 25/9
E. 10/3

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Re: Four containers of flour are on the table: The first contains 1/3 of a  [#permalink]

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08 Feb 2019, 03:24
Bunuel wrote:
Four containers of flour are on the table: The first contains 1/3 of a pound, the second contains 1/6 of a pound, the third contains 1/9 of a pound, and the fourth contains 1/18 of a pound. If each container can hold one pound of flour, how many additional pounds of flour are required to fill all four containers?

A. 2/9
B. 2/3
C. 11/9
D. 25/9
E. 10/3

IMO E

We need to find the additional pounds

1/3 of a pound means 2/3 is remaining

1/6 of a pound means 5/6 is remaining

1/9 of a pound means 8/9 is remaining

1/18 of a pound means 17/18 is remaining

Remaining will be the additional required = 2/3 + 5/6 + 8/9 +17/18 = 60 / 18
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Re: Four containers of flour are on the table: The first contains 1/3 of a  [#permalink]

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08 Feb 2019, 03:28
Bunuel wrote:
Four containers of flour are on the table: The first contains 1/3 of a pound, the second contains 1/6 of a pound, the third contains 1/9 of a pound, and the fourth contains 1/18 of a pound. If each container can hold one pound of flour, how many additional pounds of flour are required to fill all four containers?

A. 2/9
B. 2/3
C. 11/9
D. 25/9
E. 10/3

First = (1/3)

Second = (1/6)

Third = (1/9)

Fourth = (1/18)

Total Capacity = 1+1+1+1 = 4 pound

Total Availability of Flour = (1/3) + (1/6) + (1/9) + (1/18) = (6+3+2+1) / 18 = 12/18 = 2/3 pound

Addition Four needed to fill the containers = 4 - (2/3) = 3 1/3 = 10/3 pound

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Re: Four containers of flour are on the table: The first contains 1/3 of a  [#permalink]

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08 Feb 2019, 05:35
Bunuel wrote:
Four containers of flour are on the table: The first contains 1/3 of a pound, the second contains 1/6 of a pound, the third contains 1/9 of a pound, and the fourth contains 1/18 of a pound. If each container can hold one pound of flour, how many additional pounds of flour are required to fill all four containers?

A. 2/9
B. 2/3
C. 11/9
D. 25/9
E. 10/3

containers are filled : 1/3+1/6+1/9 +1/18 = 12/18 = 2/3
total capacity = 1+1+1+1 = 4
we can fill 4-2/3 = 10 /3
IMO E
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Re: Four containers of flour are on the table: The first contains 1/3 of a   [#permalink] 08 Feb 2019, 05:35
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