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# George can fill Q cans of paint in 3 minutes. If there are R cans of

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Math Expert
Joined: 02 Sep 2009
Posts: 57287
George can fill Q cans of paint in 3 minutes. If there are R cans of  [#permalink]

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08 Jun 2016, 10:04
1
11
00:00

Difficulty:

25% (medium)

Question Stats:

74% (01:51) correct 26% (01:46) wrong based on 230 sessions

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George can fill Q cans of paint in 3 minutes. If there are R cans of paint in one gallon, how many gallons can George fill in 45 minutes?

A. 30R/Q.
B. 15R/Q.
C. 30Q/R.
D. 5Q/R.
E. 15Q/R.

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Joined: 02 Mar 2012
Posts: 283
Schools: Schulich '16
Re: George can fill Q cans of paint in 3 minutes. If there are R cans of  [#permalink]

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08 Jun 2016, 10:24
E

1 can , time taken =3/Q

for R cans =3R/Q

rate for R cans =Q/3R

Apply work formula for 45 min
Q/3R *45= 15Q/R
Manager
Joined: 19 Dec 2015
Posts: 110
Location: United States
GMAT 1: 720 Q50 V38
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Re: George can fill Q cans of paint in 3 minutes. If there are R cans of  [#permalink]

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08 Jun 2016, 10:25
1
George can fill Q cans of paint in 3 minutes. So in 45 mins , he can fill 45/3 = 15Q cans.
R cans = 1 gallons => 15Q cans = 15Q/R gallons. Hence the answer is E.
Math Expert
Joined: 02 Aug 2009
Posts: 7754
Re: George can fill Q cans of paint in 3 minutes. If there are R cans of  [#permalink]

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08 Jun 2016, 10:26
1
Bunuel wrote:
George can fill Q cans of paint in 3 minutes. If there are R cans of paint in one gallon, how many gallons can George fill in 45 minutes?

A. 30R/Q.
B. 15R/Q.
C. 30Q/R.
D. 5Q/R.
E. 15Q/R.

Q cans in 3 minutes, so 15Q in 3*15 minutes.....
But we have to answer in terms of gallons and 1 gallon = R cans...
so in gallons 15Q =$$\frac{15Q}{R}$$..
E
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Joined: 22 May 2016
Posts: 3281
George can fill Q cans of paint in 3 minutes. If there are R cans of  [#permalink]

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06 Jul 2017, 10:11
Bunuel wrote:
George can fill Q cans of paint in 3 minutes. If there are R cans of paint in one gallon, how many gallons can George fill in 45 minutes?

A. 30R/Q.
B. 15R/Q.
C. 30Q/R.
D. 5Q/R.
E. 15Q/R.

Another way: Choose numbers that are factors and/or multiples of 3 and 45. I set up proportion first to avoid inverting Q and R:

Q cans of paint in 3 minutes

$$\frac{Q cans}{3 mins}$$ = $$\frac{X cans}{45 mins}$$

Let Q cans = 9
Let R, # of cans of paint in one gallon = 3

How many gallons do Q cans contain? 9 cans divided by 3 cans per gallon = 3 gallons.

Change the proportion units, where Q = 3 gallons:

$$\frac{3 gallons}{3 mins}$$ = $$\frac{X gallons}{45 mins}$$

X = 45 gallons

Check answer choices with Q = 9, R = 3, looking for answer that yields 45

A. 30R/Q = 90/9 = 10. NO
B. 15R/Q = 45/9 = 5. NO
C. 30Q/R = 270/3 = 90. NO
D. 5Q/R = 45/3 = 15. NO
E. 15Q/R = 135/3 = 45. YES

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Joined: 06 Nov 2014
Posts: 1877
Re: George can fill Q cans of paint in 3 minutes. If there are R cans of  [#permalink]

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06 Jul 2017, 10:30
Bunuel wrote:
George can fill Q cans of paint in 3 minutes. If there are R cans of paint in one gallon, how many gallons can George fill in 45 minutes?

A. 30R/Q.
B. 15R/Q.
C. 30Q/R.
D. 5Q/R.
E. 15Q/R.

Cans / minute = Q/3

1 can of pain has 1/R gallon

Hence gallons filled / minute = Q/3R

Gallons filled in 45 mins = 45 * Q/3R = 15*Q/R

Correct Option: E
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Joined: 01 Oct 2018
Posts: 14
Location: India
Concentration: Technology, Social Entrepreneurship
GPA: 3.88
George can fill Q cans of paint in 3 minutes. If there are R cans of  [#permalink]

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17 Jul 2019, 01:26
4
In 3 minutes total cans filled = Q
required in 45 minutes = Q/3 * 45 = 15Q

R cans comprises of 1 Gallon
so 15Q cans - 15Q/R Gallons

George can fill Q cans of paint in 3 minutes. If there are R cans of   [#permalink] 17 Jul 2019, 01:26
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