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The answer according to me is B, only 2nd statement is sufficient.
It is given in the question that we have to find, [x/(x+y)]*100. Let's assume it to be P.
According to the first statement, 100*[(x+2)/(x+y)]=2P. Subtracting the above equation from this equation, P=2/(x+y)=x/(x+y). Here, although we are able to find the value of x, due to y being unknown we can't find the volume ratio.
Now, according to the 2nd statement, [(x+0.5y)/(x+y)]*100=2P. From this equation, we'll get that y=2x. Using this in the original equation, we get (x/3x)*100, i.e. 33.33%
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­Percentage of orange juice = x / (x + y) * 100%
We need both x and y or we need a relationship between the two such that all variables can be eliminated on simplifciation. 

Statement (1): If 2 liters of carrot juice were replaced with 2 liters of orange juice, the percentage of orange juice by volume in the mixture would double.

If 2 liters of carrot juice were replaced with 2 liters of orange juice, the new ratio would be: (x + 2) / (x + y) * 100% = 2 * [x / (x + y) * 100%]
Note that the volume is still the same as now we have (x + 2) + (y - 2)

 (x + 2) / (x + y) = 2x / (x + y)
 => x + 2 = 2x => x = 2
So x = 2, but we still don't know y. This statement alone is not sufficient.

Statement (2):  If half of the carrot juice by volume were replaced with an equal amount of orange juice, the percentage of orange juice by volume in the mixture would double. 

If half of the carrot juice (y/2) were replaced with orange juice, the new ratio would be: (x + y/2) / (x + y) * 100% = 2 * [x / (x + y) * 100%]

 (x + y/2) / (x + y) = 2x / (x + y)
=> x + y/2 = 2x => y/2 = x
Thus x = y/2, or y = 2x.
This relationship alone is sufficient to calculate the percentage: Percentage of orange juice = x / (x + 2x) * 100% = x / 3x * 100% = 33.33%
Here, we got a relationship that's sufficient to eliminate all variables. 

Therefore, statement (2) alone is sufficient to answer the question. The correct answer is B.­
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­Let orange juice in the mixture is x litres and carrot juice is y litres 
Then % orange juice  = x/(x+y)*100

(1) Orange juice new = x+2 litres
Carrot juice new = y-2
Total remains the same = (x+y)
Then, (x+2)/(x+y)=2*x/(x+y)
=> x=2 litres. 
we don't know y. So, insufficient

(2) Carrot juice new = y/2
Orange juice new = x+y/2
Total remains the same = (x+y)
Then, (x+y/2)/(x+y) = 2(x/(x+y))
=> x=y/2 or y=2x
As we don't know either. Statement is insufficient

Now (1)+(2) 
x= 2, y=4 and %orange juice = 2/6*100 = 33.33% Sufficient

Answer: Option D

 
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A mixture of orange and carrot juices consists of x liters of orange juice and y liters of carrot juice. What percent of the mixture, by volume, is orange juice?

(1) If 2 liters of carrot juice were replaced with 2 liters of orange juice, the percentage of orange juice by volume in the mixture would double.

(2) If half of the carrot juice by volume were replaced with an equal amount of orange juice, the percentage of orange juice by volume in the mixture would double.­

The ask of the question is x / (x+y) * 100

Statement (1):
x+2 / (x+2 + y-2) = 2x / (x+y), which tells us that x + 2 = 2x, implies x = 2. But we don't have information of y hence we can't know the %age of the mixture. Hence INSUFF
(For example if you keep y = 8, you will get 20%, but if you keep y = 3, you will get 40%)

Statement (2): (x + y/2) / (x + y/2 + y - y/2) = 2x / (x + y), which tells us that x + y/2 = 2x, from this we know that 2x + y = 4x OR y = 2x. Using this we can know the %age of the mixture, hence SUFF 

So the answer will be (B)
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Given: A mixture of orange and carrot juices consists of x liters of orange juice and y liters of carrot juice.
Asked: What percent of the mixture, by volume, is orange juice?

The percent of the mixture, by volume, is orange juice = x/(x+y)

(1) If 2 liters of carrot juice were replaced with 2 liters of orange juice, the percentage of orange juice by volume in the mixture would double.
Carrot Juice becomes = y-2
Orange Juice becomes = x+2
(x+2)/(x+2+y-2) = (x+2)/(x+y) = 2*x/(x+y)
2x = x+2; x = 2
Since the value of y can not be ascertained.
NOT SUFFICIENT

(2) If half of the carrot juice by volume were replaced with an equal amount of orange juice, the percentage of orange juice by volume in the mixture would double.
Carrot Juice becomes = y/2
Orange Juice becomes = x + y/2
(x+y/2)/(x+y/2+y/2) = (x+y/2)/(x+y) = 2x/(x+y)
x + y/2 = 2x
x = y/2; y = 2x
The percent of the mixture, by volume, is orange juice = x/(x+y) = x/(x+2x) = 1/3
SUFFICIENT

IMO B
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A mixture of orange and carrot juices consists of x liters of orange juice and y liters of carrot juice. What percent of the mixture, by volume, is orange juice?
we are looking for x/(x+y) (*)


(1) If 2 liters of carrot juice were replaced with 2 liters of orange juice, the percentage of orange juice by volume in the mixture would double.
In this case, (x+2)/(x+y) = 2.x/(x+y) -->x+2=2x -> x=2 this is not sufficient, since we do not know y

(2) If half of the carrot juice by volume were replaced with an equal amount of orange juice, the percentage of orange juice by volume in the mixture would double.

In this case we have, (x+y/2)/x+y = 2. x/ (x+y)--> x+y/2 = 2x --> x=y/2 and if we plug this in (*)
we can have : x/(x+y) (which is the ratio we're looking for) = 1/3, and this is sufficient, Correct answer is B
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Ans D

Given: volume of Orange juice= x volume of carrot juice = y
% of orange juice in the mixture = x/(x+y) *100

(1) 2x/(x+y)*100 = (x+2)/(x+y)*100
      2x=x+2
       x=2
    We do not know value of y. Not sufficient
(2) 2x/(x+y)=(x+(y/2))/(x+y)
     x=y/2

   substituting this in x/(x+y) we can get % of orange juice in the mixture.

   Hence, sufficient
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Quote:
­A mixture of orange and carrot juices consists of x liters of orange juice and y liters of carrot juice. What percent of the mixture, by volume, is orange juice?
target ; x/ ( x+y)

(1) If 2 liters of carrot juice were replaced with 2 liters of orange juice, the percentage of orange juice by volume in the mixture would double.

x+2 , y-2
x+2 / ( x+y ) = 2 * ( x/ x+y)
x = 2
but value y cannot be determined
insufficient

(2) If half of the carrot juice by volume were replaced with an equal amount of orange juice, the percentage of orange juice by volume in the mixture would double.

y-.5 , x+.5
same as #1
insufficient
from 1 & 2 we cannot determine target
OPTION E 
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Bunuel
A mixture of orange and carrot juices consists of x liters of orange juice and y liters of carrot juice. What percent of the mixture, by volume, is orange juice?

(1) If 2 liters of carrot juice were replaced with 2 liters of orange juice, the percentage of orange juice by volume in the mixture would double.

(2) If half of the carrot juice by volume were replaced with an equal amount of orange juice, the percentage of orange juice by volume in the mixture would double.

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked.
C. BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked.
D. EACH statement ALONE is sufficient to answer the question asked.
E. Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data specific to the problem are needed.


­
 


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­
­B since statement 1 said 2 liters but they didn't mention anything about the total volume of OJ or CJ nor the relationship between 2l and x or y. Statement 2 mention the relationship between the whole volume so we can figure out the ratio of the OJ so I chose B 
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Bunuel
A mixture of orange and carrot juices consists of x liters of orange juice and y liters of carrot juice. What percent of the mixture, by volume, is orange juice?

(1) If 2 liters of carrot juice were replaced with 2 liters of orange juice, the percentage of orange juice by volume in the mixture would double.

(2) If half of the carrot juice by volume were replaced with an equal amount of orange juice, the percentage of orange juice by volume in the mixture would double.

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked.
C. BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked.
D. EACH statement ALONE is sufficient to answer the question asked.
E. Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data specific to the problem are needed.


­
 


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­
­We require x/(x+y)*100

Statement 1
(x+2)/(x+y)=2x/(x+y) => x=2. Not sufficient as we dont know Y

Statement 2 
(x+y/2)/(x+y)=2x/(x+y)
x=y/2 Suffcient.

IMO B
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Answer B
­II. Sufficient
Explanation: If carrot halves, and by that orange doubles, than the ratio of carrot to orange is 2:1 , because if I take half of 2 which is one and add to 1 that doubles to 2. So with that we know the percentage of oragne in the mixture
I. Not sufficient because I know that I have 2l of orange in the mixture because the only way to double if I add two liters, is to already have two liters. The thing is we don't know how much carrot juice in the mixture there is so we don't know the denominator value.
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IMO -B.

Orange Juice = x liters and Carrot Juice = y liters. We need to find x/ (x+y)*100

St1 (x+2)/(x+2+y-2) = 2(x/(x+y))

with this statement we get the value of x=2. But we cannot find the value of y. hence insufficient.

St2

y-(y/2) and x+(y/2).

We can substitute this into the equation we will get the relationship between x and y. thus we can find the value of percentage.
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What is x/(x+y)?

S1) (x+2)/(x+y)=2x/(x+y)
=>x=2, y is unkwown (NS)

S2) (x+y/2)/(x+y)=2x/(x+y)
=> x=y/2, this can give 2/(x+y) (Suff)

B)
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Given
orange x
carrot y

(x / (x+y))*100%

statement 1
orange x+2
carrot y-2

(2x / (x+y)) = ((x+2)/(x+y))
x = 2, y = ?
Not Sufficient.

Statement 2.
orange x+y/2
carrot y/2

(2x / (x+y)) = ((x+y/2)/(x+y/2+y/2))
y = 2x

Plug-in (x / (x+y))*100% = 33.3%
Sufficient

IMO. B
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­Given - A mixture of orange and carrot juices consists of x liters of orange juice and y liters of carrot juice.
Orange = x liters and Carrot = y liters

To find - What percent of the mixture, by volume, is orange juice?
%Volume of orange juice = \(\frac{x}{x+y}\) ­* 100­        ----------Eq1

1st - If 2 liters of carrot juice were replaced with 2 liters of orange juice, the percentage of orange juice by volume in the mixture would double.
After Replacement,
Carrot juice = y-2 liters
Orange juice = x+2 liters
Net combine remains same = x+y liters.

%Volume of orange juice after replacement = \(\frac{x+2}{x+y}\) ­* 100­ = 2*\(\frac{x}{x+y}\) ­* 100­
 ­After simplifying,
\(x+2 = 2x\)
x=2 liters.
But to calculate %Volume for orange juice we will need value of y liters as well, but there is nothing which relates y hence not sufficient.

 2nd - If half of the carrot juice by volume were replaced with an equal amount of orange juice, the percentage of orange juice by volume in the mixture would double.
After Replacement,
Carrot juice = \(\frac{y}{2}\) liters
Orange juice = \(x+\frac{y}{2}\) liters
Net combine remains same = \(x+y\) liters.
 ­
%Volume of orange juice after replacement = ((x+(y/2))/(x+y))­* 100­ = 2*\(\frac{x}{x+y}\) ­* 100­
After simplifying,
\(\frac{(2x+y)}{2(x+y)}­\)* 100­ = 2*\(\frac{x}{x+y}\) ­* 100­
on further simplification,
y=2x.
Substitute in eq1,
%Volume of orange juice = \(\frac{x}{x+2x}\) ­* 100­ = \(\frac{1}{3}\) * 100 = 33.33%
Sufficient.
Answer B.­
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x liters of orange juice
y liters of carrot juice
\(x+y\) liters - the total volume of the mixture
Percentage of orange juice per volume :­ \(\frac{x}{x+y}\)

(1) \(x+2\) liters of orange juice
     \(y-2\) liters of carrot juice
     \(x+2+y-2=x+y\) liters of the mixture

Percentage of orange juice per volume :­ \(\frac{x+2}{x+y}\)
The percentage of orange juice by volume in the mixture would double, so \(\frac{x+2}{x+y}\)=\(\frac{2x}{x+y}\)
After some claculations we receive the value of x, \(x=2\)
However, we can't find y. So this statement alone if not sufficient 

(2) \(x+\frac{y}{2}\) liters of orange juice 
     \(\frac{y}{2}\) liters of carrot juice
     \(x+\frac{y}{2}+\frac{y}{2}=x+y\) liters of the mixture

Percentage of orange juice per volume:
\(\frac{x+\frac{y}{2}}{x+y}\)

The percentage of orange juice by volume in the mixture would double, so  \(\frac{x+\frac{y}{2}}{x+y}=\frac{2x}{x+y}\)

We can't solve this equation without knowing value of x or y. So this statement alone is not sufficient.
However, we know the value of x, we plug it in and find that \(y=4\)

\(\frac{2}{2+4}=0,(3),\) so around 33% of mixture by volume is orange juice

Thus, the right answer is C. BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient to answer the question asked.­
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­We need to find \(\frac{x}{x+y}\) as a percentage
(1) If 2 liters of carrot juice were replaced with 2 liters of orange juice, the percentage of orange juice by volume in the mixture would double.
\(\frac{x+2}{x+2+y-2}=\frac{2x}{x+y}\)
We can see this to be insufficient. x+y gets cancelled and we can't find percentage of orange juice. 
(2) If half of the carrot juice by volume were replaced with an equal amount of orange juice, the percentage of orange juice by volume in the mixture would double.
Here also, the same thing will happen - the denominator will be x+y even after replacing half of the volume of carrot juice with orange since x+y/2+y/2 will be the new denominator. 
Both together: 
Hence, both together are also insufficient since we don't get the value of x+y and the solution can't be found.  ­
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