Question stem provide us with following information,
Mix juice = x litre of orange + y litre of carrot.
We need to find percent of the mixture, by volume, is orange juice.
So,
we need to find \(\frac{100x }{ x+y}\)
Statement-1 If 2 liters of carrot juice were replaced with 2 liters of orange juice, the percentage of orange juice by volume in the mixture would double.
So, new carrot juice = \(y - 2 \)
new orange juice = \(x + 2\)
total =\( x+y-2+2 = x+y\)
And percentage of orange juice by volume in the mixture would double compared to original.
\(100 *\frac{ x+2 }{ x+y}\) = \(\frac{2*100x }{ x+y}\)
\( x + 2 = 2x\)
\(x = 2\)
But we don't know value of \(y\).
So statement is insufficient.
Statement-2 If half of the carrot juice by volume were replaced with an equal amount of orange juice, the percentage of orange juice by volume in the mixture would double.
new carrot juice = \(\frac{y}{2}\)
new orange juice = \(x + \frac{y}{2}\)
new total = \(x + \frac{y}{2} + \frac{y}{2}\) = \(x + y\)
the percentage of orange juice by volume in the mixture would double compared to original.
\(100 *\frac{ x+ 0.5y }{ x+y}\) = \(\frac{2*100x }{ x+y}\)
\( x+0.5y = 2x \)
\(y = 2x\)
We can find \(\frac{100x }{ x+y}\) from this.
= \(\frac{100x }{ x+y}\)
= \(\frac{100x }{ x+2x}\)
= \(\frac{100}{3}\) %
Statement-2 is sufficientFinal answer is
B.Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked.