Manonamission wrote:
How many diagonals does a polygon with 18 sides have if three of its vertices, which are adjacent to each other, do not send any diagonals?
A. 10
B. 25
C. 58
D. 90
E. 91
OFFICIAL EXPLANATION FROM VERITAS PREP
We will use two different methods to solve this question:
Method 1:
Number of diagonals in a polygon of 18 sides = 18*(18 – 3)/2 = 135 diagonals
Each vertex makes a diagonal with
n-3 other vertices.
So each vertex will make 15 diagonals.
Total number of diagonals if 3 vertices do not send any diagonals = 135 – 15*3 = 90 diagonals.
Method 2:
The polygon has a total of 18 vertices.
3 vertices do not participate so we need to make all diagonals that we can with 15 vertices.
Number of lines you can make with
15 vertices = 15C2 = 15*14/2 = 105
But this 105 includes the sides as well. A polygon with 18 vertices has 18 sides. Since 3 adjacent vertices do not participate, 4 sides will not be formed. 15 vertices will have 14 sides which will be a part of the 105 we calculated before.
Total number of diagonals if 3 vertices do not send any diagonals = 105 – 14 =
91Note that the two answers do not match. Method 1 gives us 90 and method 2 gives us 91. Both methods look correct but only one is actually correct. Your job is to tell us which method is correct and why the other method is incorrect.
_________________
"Be challenged at EVERY MOMENT."“Strength doesn’t come from what you can do. It comes from overcoming the things you once thought you couldn’t.”"Each stage of the journey is crucial to attaining new heights of knowledge."Rules for posting in verbal forum | Please DO NOT post short answer in your post!
Advanced Search : https://gmatclub.com/forum/advanced-search/